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3 years ago

How many nitrogen atoms are present in 0.150 mol of zn(no3)2?

1 answer:

8 0

First calculate number of Nitrogen atoms contained by 1 mole of Zn(NO₃)₂,

As one formula unit of Zn(NO₃)₂ contains 2 Nitrogen atoms, then one mole of Zn(NO₃)₂ will contain,

= 2 × 6.022 × 10²³

= 1.20 × 10²⁴ Atoms of Nitrogen / mole

Now, calculate number of Nitrogen Atoms in 0.150 moles of  Zn(NO₃)₂.
As,
1 mole of  Zn(NO₃)₂ contained = 1.20 × 10²⁴ atoms of N
Then,
0.15 mole of  Zn(NO₃)₂ will contain = X atoms of N
Solving for X,

X = (0.15 mol × 1.20 × 10²⁴ atom) ÷ 1 mol

X = 1.80 × 10²⁴ Atoms of Nitrogen
Result:
So, 0.15 mole of  Zn(NO₃)₂ contains 1.80 × 10²⁴ atoms of Nitrogen.

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4 years ago

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4 years ago

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4 years ago

Look at the question marks between zinc (Zn) and arsenic (As) . At the time no elements were known with atomic weights between 6

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Mendeleev found that two elements existed between atomic weights 65.2 and 75 because he comprehended especially pleasingly that the possessions of the elements were more comparable and closer to this degree.

He also anticipated having other elements that would have their possessions comparable to these other elements.

Therefore, he departed a void for these two elements in the periodic table until they were ultimately found in their real existence.

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Look at the two question marks between zinc (Zn) and arsenic (As). At the time, no elements were known with atomic weights between 65.2 and 75. But Mendeleev predicted that two elements must exist with atomic weights in this range. What led Mendeleev to predict that two undiscovered elements existed in that range?

Therefore, it is well described above.

To learn more about Mendeleev's periodic table, refer to the link:

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2 years ago

Find the hydrogen ion concentration of a saturated solution of calcium hydroxide whose ph is 13. 1

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