Picture included please help

Jeremy bought a 5-pound bag of potatoes for$2.29. What is the unit price for one pound of potatoes?

Lerok [7]

Answer: .458 or about .46 cents if you round to the nearest cent

Step-by-step explanation:Since the price for 5 pounds of potatoes is 2.29 all together you can divide 2.29 by 5 which gives you the price for one pound of potatoes. Since one pound of potatoes would be the unit price. Hope this helps :D

3 0

2 years ago

Which expression is equivalent to the expression shown (5^3) ^9 divided 5^12

weqwewe [10]

Answer:5 exponent of 15

Step-by-step explanation:trust

5 0

3 years ago

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How do I solve operations with absolute value [10-11]-[15]

saveliy_v [14]

[10-11] - [15]
=[21] -[15]
= [6]

anything inside the absolute bracket would have to remain positive, anything outside wouldn't change

6 0

3 years ago

Find the sum of 2x 2 + 3x - 4, 8 - 3x, and -5x 2 + 2.

RSB [31]

The sum is -7x2-6x-2

6 0

3 years ago

Suppose θ is an angle in the standard position whose terminal side is in Quadrant III and sec θ=61/60. Find the exact values of

Nataly_w [17]

Answer:

Part 1) $cos(\theta)=-\frac{60}{61}$

Part 2) $tan(\theta)=\frac{11}{60}$

Part 3) $cot(\theta)=\frac{60}{11}$

Part 4) $csc(\theta)=-\frac{61}{11}$

Part 5) $sin(\theta)=-\frac{11}{61}$

Step-by-step explanation:

we know that

If angle theta lie on Quadrant III

then

The function sine is negative

The function cosine is negative

The function tangent is positive

The function cotangent is positive

The function cosecant is negative

The function secant is negative

step 1

Find $cos(\theta)$

we know that

$cos(\theta)=\frac{1}{sec(\theta)}$

we have

$sec(\theta)=-\frac{61}{60}$ ----> the value must be negative

therefore

$cos(\theta)=-\frac{60}{61}$

step 2

Find $tan(\theta)$

we know that

$tan^{2} (\theta)+1=sec^{2} (\theta)$

we have

$sec(\theta)=-\frac{61}{60}$

substitute

$tan^{2} (\theta)+1=(-\frac{61}{60})^{2}$

$tan^{2} (\theta)+1=\frac{3,721}{3,600}$

$tan^{2} (\theta)=\frac{3,721}{3,600}-1$

$tan^{2} (\theta)=\frac{121}{3,600}$

$tan(\theta)=\frac{11}{60}$

step 3

Find $cot(\theta)$

we know that

$cot(\theta)=\frac{1}{tan(\theta)}$

we have

$tan(\theta)=\frac{11}{60}$

therefore

$cot(\theta)=\frac{60}{11}$

step 4

Find $csc(\theta)$

we know that

$cot^{2} (\theta)+1=csc^{2} (\theta)$

we have

$cot(\theta)=\frac{60}{11}$

substitute

$(\frac{60}{11})^{2}+1=csc^{2} (\theta)$

$\frac{3,600}{121}+1=csc^{2} (\theta)$

$\frac{3,721}{121}=csc^{2} (\theta)$

square root both sides

$csc(\theta)=-\frac{61}{11}$

step 5

Find $sin(\theta)$

we know that

$sin(\theta)=\frac{1}{csc(\theta)}$

we have

$csc(\theta)=-\frac{61}{11}$

therefore

$sin(\theta)=-\frac{11}{61}$

7 0

2 years ago

Read 2 more answers