For the part a) we need only the momentum of the box and we have the data to find it.
Momentum is given by,

where clearly, p is the momentum, m the mass of the box and v is the velocity.
Substituting,

For part b) we need an analysis of the situation. We understand that the box on a surface that has no friction will continue to rotate at the same speed previously defined. The box can only stop with friction, so,

<em>It is the same that part a)</em>
Answer:
<h2> 1.643*10⁻⁴cm</h2>
Explanation:
In a single slit experiment, the distance on a screen from the centre point is expressed as y =
where;
is the first two diffraction minima = 1
is light wavelength
d is the distance of diffraction pattern from the screen
a is the width of the slit
Given
= 460-nm = 460*10⁻⁹m
d = 5.0mm = 5*10⁻³m
a = 1.4mm = 1.4*10⁻³m
Substituting this values into the formula above to get width of the central maximum y;
y = 1*460*10⁻⁹ * 5*10⁻³/1.4*10⁻³
y = 2300*10⁻¹²/1.4*10⁻³
y = 1642.86*10⁻⁹
y = 1.643*10⁻⁶m
Converting the final value to cm,
since 100cm = 1m
x = 1.643*10⁻⁶m
x = 1.643*10⁻⁶ * 100
x = 1.643*10⁻⁴cm
Hence, the width of the central maximum in the diffraction pattern on a screen 5.0 mm away is 1.643*10⁻⁴cm
Explanation:
step 1. a diverging lens is "concave" on both side and always has a negative focal length
step 2. so 1/f = 1/s + 1/s' where f is the focal length, s is the object location, and s' is the image location (f, s, s' are all on the left side of the lens)
step 3. 1/-15 = 1/s + 1/-9 (image is virtual (negative))
step 4. 3/-45 = 1/s + 5/-45
step 5. s = 22.5cm (object is 22.5cm from lens)
step 6. s'/s = 9/22.5 ÷ 0.4 (magnification)
step 7. if the object is 4.5cm then the image is 4.5(0.4) = 1.8cm tall.