Answer:
yes. why do you need this answered asap? lol
Answer:
a) 588,000 N
b) 294000 N
Explanation:
Given that
Density of water = 1000kg/m3
(g) = 9.8m/s2
volume is given as (V)= 5m*4m*3m
a) force will be equal to weight of water
![W = mg = \rho g V = 1000\times 9.8 \times (5*4*3) = 588,000 kg m/s^2](https://tex.z-dn.net/?f=W%20%3D%20mg%20%20%3D%20%5Crho%20g%20V%20%3D%201000%5Ctimes%209.8%20%5Ctimes%20%285%2A4%2A3%29%20%3D%20588%2C000%20kg%20m%2Fs%5E2)
b) at either end
![P = \frac{F}{A} = P_o + \rho gh](https://tex.z-dn.net/?f=P%20%3D%20%5Cfrac%7BF%7D%7BA%7D%20%3D%20P_o%20%2B%20%5Crho%20gh)
![dF = PdA](https://tex.z-dn.net/?f=dF%20%3D%20PdA)
![dF = \rho g w \int h dh](https://tex.z-dn.net/?f=dF%20%3D%20%5Crho%20g%20w%20%5Cint%20h%20dh)
![F = \rho g w \frac{h^2}{2}](https://tex.z-dn.net/?f=F%20%3D%20%5Crho%20g%20w%20%5Cfrac%7Bh%5E2%7D%7B2%7D)
[A = wh]
![F = 1000\times 9.8 \times 5\times 4 \times\frac{3}{2}](https://tex.z-dn.net/?f=F%20%3D%201000%5Ctimes%209.8%20%5Ctimes%205%5Ctimes%204%20%5Ctimes%5Cfrac%7B3%7D%7B2%7D)
F = 294000 N
Answer:
69.68 N
Explanation:
Work done is equal to change in kinetic energy
W = ΔK = Kf - Ki = ![\frac{1}{2} mv^{2} _{f} - \frac{1}{2} mv^{2} _{i}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20mv%5E%7B2%7D%20_%7Bf%7D%20%20-%20%5Cfrac%7B1%7D%7B2%7D%20mv%5E%7B2%7D%20_%7Bi%7D)
W = ![F_{total} .d](https://tex.z-dn.net/?f=F_%7Btotal%7D%20.d)
where m = mass of the sprinter
vf = final velocity
vi = initial velocity
W = workdone
kf = final kinetic energy
ki = initial kinetic energy
d = distance traveled
Ftotal = total force
vf = 8m/s
vi= 2m/s
d = 25m
m = 60kg
inserting parameters to get:
W = ΔK = Kf - Ki = ![\frac{1}{2} mv^{2} _{f} - \frac{1}{2} mv^{2} _{i}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20mv%5E%7B2%7D%20_%7Bf%7D%20%20-%20%5Cfrac%7B1%7D%7B2%7D%20mv%5E%7B2%7D%20_%7Bi%7D)
![F_{total} .d =\frac{1}{2} mv^{2} _{f} - \frac{1}{2} mv^{2} _{i}](https://tex.z-dn.net/?f=F_%7Btotal%7D%20.d%20%3D%5Cfrac%7B1%7D%7B2%7D%20mv%5E%7B2%7D%20_%7Bf%7D%20%20-%20%5Cfrac%7B1%7D%7B2%7D%20mv%5E%7B2%7D%20_%7Bi%7D)
![F_{total} = \frac{\frac{1}{2} mv^{2} _{f} - \frac{1}{2} mv^{2} _{i}}{d}](https://tex.z-dn.net/?f=F_%7Btotal%7D%20%3D%20%5Cfrac%7B%5Cfrac%7B1%7D%7B2%7D%20mv%5E%7B2%7D%20_%7Bf%7D%20-%20%5Cfrac%7B1%7D%7B2%7D%20mv%5E%7B2%7D%20_%7Bi%7D%7D%7Bd%7D)
![F_{total=} \frac{\frac{1}{2} X 62 X6^{2} -\frac{1}{2} X 62 X2^{2} }{25}](https://tex.z-dn.net/?f=F_%7Btotal%3D%7D%20%5Cfrac%7B%5Cfrac%7B1%7D%7B2%7D%20X%2062%20X6%5E%7B2%7D%20-%5Cfrac%7B1%7D%7B2%7D%20X%2062%20X2%5E%7B2%7D%20%7D%7B25%7D)
= 39.7
we know that the force the sprinter exerted F sprinter, the force of the headwind Fwind = 30N
![F_{sprinter} = F_{total} + F_{wind} = 39.7 + 30 = 69.68 N](https://tex.z-dn.net/?f=F_%7Bsprinter%7D%20%3D%20F_%7Btotal%7D%20%2B%20F_%7Bwind%7D%20%20%3D%2039.7%20%2B%2030%20%3D%2069.68%20N)