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3 years ago

A car traveling 91 km/h is 280 m behind a truck traveling 76 km/h.

Physics

1 answer:

Olegator [25]3 years ago

6 0

Answer:

speed of car = 95 km/h

speed of truck = 75 km/h

relative speed of car with respect to truck = 95 - 75 = 20 km/h

now we will convert it into m/s

now time to cross the truck will be given as

time = 19.8 s

so it will take 19.8 s to cross the truck

Explanation:

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A 1.5m wire carries a 3 A current when a potential difference of 86 V is applied. What is the resistance of the wire?

Iteru [2.4K]

We know, R = V / I
Here, V = 86 V
I = 3 A

Substitute their values,
R = 86 / 3
R = 28.67 Ohm

In short, Your Answer would be 28.67 Ohms

Hope this helps!

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3 years ago

Where is earth's magnetic north pole located?

andre [41]

Answer: it is located over Ellesmere Island, Canada

Explanation

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2 years ago

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A deuteron, 21H, is the nucleus of a hydrogen isotope and consists of one proton and one neutron. The plasma of deuterons in a n

Naddik [55]

Answer:

1917723.40119 m/s

Explanation:

m = Mass of deuteron = $(1.637+1.675)\times 10^{-27}=3.312\times 10^{-27}$

k = Boltzmann constant = $1.381\times 10^{-23}\ J/K$

T = Temperature = $2.94\times 10^8\ K$

RMS velocity is given by

$V_r=\sqrt{\dfrac{3kT}{m}}\\\Rightarrow V_r=\sqrt{\dfrac{3\times 1.381\times 10^{-23}\times 2.94\times 10^8}{3.312\times 10^{-27}}}\\\Rightarrow V_r=1917723.40119\ m/s$

The RMS velocity of the deutrons is 1917723.40119 m/s

8 0

3 years ago

3. According to the Guinness Book of Records the heaviest baby ever born weighed 29 lbs 4 oz. (29.25 lbs).

Alexxandr [17]

Answer: 13.2678 kg

Explanation: Well, 13.2678 kg is 29.25 in mass and kg.

6 0

3 years ago

By what factor is the intensity of sound at a rock concert louder than that of a whisper when the two intensity levels are 120 d

Kipish [7]

Answer:

The intensity of sound at a rock concert is louder than that of a whisper by a factor of 1 x 10¹⁰

Explanation:

Given;

rock concert sound intensity level, β₁ = 120 dB

whisper sound intensity level, β₂ = 20 dB

The sound intensity level is given as;

$\beta = 10Log(\frac{I}{I_o} )\\\\$

where;

I₀ is the threshold sound intensity of hearing = 10⁻¹² W/m²

I is the sound intensity

Intensity of sound at rock concert ;

$120 = 10Log(\frac{I}{10^{-12}} )\\\\12 = Log(\frac{I}{10^{-12}} )\\\\10^{12} = \frac{I}{10^{-12}}\\\\I = 10^{12} * 10^{-12}\\\\I = 10^0\\\\I = 1 \ W/m^2$

The intensity of sound of a whisper;

$20 = 10Log(\frac{I}{10^{-12}} )\\\\2 = Log(\frac{I}{10^{-12}} )\\\\10^{2} = \frac{I}{10^{-12}}\\\\I = 10^{2} * 10^{-12}\\\\I = 10^{-10} \ W/m^2\\\\$

Determine the factor by which the intensity of sound at a rock concert louder than that of a whisper

$\frac{I_{Concert}}{I_{whisper}} = \frac{1}{10^{-10}} \\\\\frac{I_{Concert}}{I_{whisper}} = 1 * 10^{10}\\\\I_{Concert} = 1 * 10^{10}*I_{whisper}$

Therefore, the intensity of sound at a rock concert is louder than that of a whisper by a factor of 1 x 10¹⁰

3 0

3 years ago