All categories

3 years ago

If you were to remove an electron from a sodium atom that has eleven protons, what would be the electrical charge of the ion?

Chemistry

1 answer:

damaskus [11]3 years ago

4 0

Answer:

positive one (+1)

Explanation:

sodium having atomic mass is twenty three (23) and atomic number is eleven (11).

Sodium atom having only one electron in it's outer most shell and it is easy for atom to lose this electron from outer most shell to make itself stable.

So after losing this electron positive charge on the upper right side of the atom will occur with the number of electron lose that is Na+1 .

You might be interested in

_________ rock's form when hot, molten rock cools and becomes a solid

zavuch27 [327]

The answer to fill in the blank is (igneous)

I hope I helped.

3 0

3 years ago

Regulations on air pollutants in the United States and other countries since the 1970s have greatly reduced the amount of CO2 em

Lynna [10]

True.

Because some people breathe less pollution and face lower risks of premature death and other serious health

7 0

2 years ago

Read 2 more answers

A 7.00-mL portion of 8.00 M stock solution is to be diluted to 0.800 M. What will be the final volume after dilution? Enter your

amm1812

Explanation:

The number of moles of solute present in liter of solution is defined as molarity.

Mathematically, Molarity = $\frac{\text{no. of moles}}{\text{Volume in liter}}$

Also, when number of moles are equal in a solution then the formula will be as follows.

$M_{1} \times V_{1} = M_{2} \times V_{2}$

It is given that $M_{1}$ is 8.00 M, $V_{1}$ is 7.00 mL, and $M_{2}$ is 0.80 M.

Hence, calculate the value of $V_{2}$ using above formula as follows.

$M_{1} \times V_{1} = M_{2} \times V_{2}$

$8.00 M \times 7.00 mL = 0.80 M \times V_{2}$

$V_{2} = \frac{56 M. mL}{0.80 M}$

= 70 ml

Thus, we can conclude that the volume after dilution is 70 ml.

7 0

2 years ago

Which is the anode and which is the cathode?

rewona [7]

Answer:

2l- ---> l2 + 2e- is the anode

2H+ + 2e- ---> H2(g) is the cathode

Explanation:

Oxidation occurs when a metal loses two or more electrons in a redox chemical reaction and reduction is when it gains. Thus, oxidation is the anode and reduction is the cathode.

5 0

3 years ago

The emission of the light waves in the lasers allows them to overlap properly to create larger waves, which means that _____ ove

Vikentia [17]

The emission of the light waves ..................... which means that THE TROUGHS OF ONE WAVE AND THE CREST OF ANOTHER overlap.
When the trough and the crest of wave overlap, it results in constructive interference and the amplitude of the two waves are added together to form a larger amplitude.<span />

5 0

3 years ago