Answer: The correct answer is : 44.1 g / mol
Explanation: d = PM / RT
M = dRT / P
d = 1.97 g / l
R = ideal gas (0.082 06 l - atm / mol - ° K)
P = 1 atm
T = 273 ° K
M = Molar mass
M = 1.97 g / l x 0.082 l - atm / mol - ° K x 273 ° K / 1 atm
M = 44.1 g / mol
The given question is incomplete. The complete question is:
Aqueous hydrochloric acid (HCl) reacts with solid sodium hydroxide (NaOH) to produce aqueous sodium chloride (NaCl) and liquid water (H2O). If 1.60 g of sodium chloride is produced from the reaction of 1.8 g of hydrochloric acid and 1.4 g of sodium hydroxide, calculate the percent yield of sodium chloride. Be sure your answer has the correct number of significant digits in it.
Answer: Thus the percent yield of sodium chloride is 78.0%
Explanation:
To calculate the moles :
According to stoichiometry :
1 mole of 
require = 1 mole of 
Thus 0.035 moles of will require=
of
Thus is the limiting reagent as it limits the formation of product and is the excess reagent.
As 1 mole of give = 1 mole of 
Thus 0.035 moles of give = of
Mass of 
Thus the percent yield of sodium chloride is 78.0%
Answer:
is simple apply formula dude.
Answer:
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Answer,
Add water to dissolve the salt solution.Shake the solution,oil and water are immiscible liquids therefore oil will not dissolve.Put the solution in a separating funnel and leave the solution undisturbed for a few minutes.Water is denser than oil there oil will come to the top.Power the lower layer of water in to a beaker.Boil the water until water turns into vapour leaving the salt behind.
