All categories

3 years ago

A temperature of 34 fereheight is equal to blank kelvin

Physics

2 answers:

Softa [21]3 years ago

8 0

274.261 in kelvin from fahrenheit

Luba_88 [7]3 years ago

3 0

Temperature of 34°F is equal to 274 K

<h3>Further explanation</h3>

Specific Heat Capacity is the amount of energy needed to raise temperature of 1 kg body for 1°C.

$\large {\boxed{Q = m \times c \times \Delta t} }$

<em>Q = Energy ( Joule )</em>

<em>c = Specific Heat Capacity ( J / kg°C ) </em>

<em>Δt = Change In Temperature ( °C )</em>

Let us now tackle the problem!

To change the unit of temperature we can use the following general formula.

$\large {\boxed {\frac{^oC}{5} = \frac{^oR}{4} = \frac{^oF - 32}{9} = \frac{K - 273}{5} } }$

To convert 34 °F into Kelvin, it can be done in the following way

$\frac{^oF - 32}{9} = \frac{K - 273}{5}$

$\frac{34 - 32}{9} = \frac{K - 273}{5}$

$\frac{2}{9} = \frac{K - 273}{5}$

$K - 273 = \frac{2}{9} \times 5$

$K = 273 + \frac{10}{9}$

$K \approx 274$

<h2>Conclusion:</h2><h3>34°F ≈ 274 K</h3>

<h3>Learn more</h3>

Efficiency of Engine : brainly.com/question/5597682
Flow of Heat : brainly.com/question/3010079
Difference Between Temperature and Heat : brainly.com/question/3821712

<h3>Answer details </h3>

Grade: College

Subject: Physics

Chapter: Thermal Physics

Keywords: Heat , Temperature , Block , Aluminium , Ice , Cold , Water , Conversion , Kelvin , Fahrenheit

You might be interested in

Periodic table of elements metals and nonmetals questions

bixtya [17]

Answer:

1 o b

2 c\

3 a

Explanation:

5 0

3 years ago

Read 2 more answers

A 500kg car skids to a stop at a traffic light, leaving behind a 18.25m skid mark as it comes to a rest. Assuming that the car i

Nastasia [14]

Answer:

Coefficient of friction will be 0.587

Explanation:

We have given mass of the car m = 500 kg

Distance s = 18.25 m

Initial velocity of the car u = 14.5 m/sec

As the car finally stops so final velocity v = 0 m/sec

From second equation of motion

$v^2=u^2+2as$

$0^2=14.5^2+2\times a\times 18.25$

$a=-5.76m/sec^2$

We know that acceleration is given by

$a=\mu g$

$5.76=\mu\times 9.81$

$\mu =0.587$

So coefficient of friction will be 0.587

6 0

3 years ago

234 oz to tons using the table method (US)

Rom4ik [11]

Answer:

234 oz = 0.0066339 t.

Explanation:

Boom Logic...

3 0

3 years ago

Lasers are now used in eye surgery. Given the wavelength of a certain laser is 514 nm and the power of the laser is 1.1 W, how m

Leno4ka [110]

Answer: $1.593*10^{17} photons$ released if the laser is used 0.056 s during the surgery

Explanation:

First, you have to calculate the energy of each photon according to Einstein's theoty, given by:

$E =\frac{hc}{\lambda}$

Where $\lambda$ is the wavelength, $h$ is the Planck's constant and $h$ is the speed of light

$h = 6.626*10^{-34} \frac{m^{2} kg }{s}$ -> Planck's constant

$c = 3*10^{8} \frac{m}{s}$ -> Speed of light

So, replacing in the equation:

$E =\frac{ 6.626*10^{-34} \frac{m^{2} kg }{s}*3*10^{8} \frac{m}{s}}{514*10^-9 m}$

Then, the energy of each released photon by the laser is:

$E = 3.867*10^{-19} \frac{J}{photons}$

After, you do the inverse of the energy per phothon and as a result, you will have the number of photons in a Joule of energy:

$\frac{1}{3.867*10^{-19}} = 2.586*10^{18} \frac{photons}{J}$

The power of the laser is 1.1 W, or 1.1 J/s, that means that you can calculate how many photons the laser realease every second:

$2.586*10^{18}\frac{photons}{J} * 1.1 \frac{J}{s} = 2.844*10^{18} \frac{photons}{s}$

And by doing a simple rule of three, if $2.844*10^{18} photons$ are released every second, then in 0.056 s:

$0.056 s*2.844*10^{18} \frac{photons}{s} = 1.593*10^{17} photons$ are released during the surgery

5 0

3 years ago

What information do we know about the known exoplanets? a. estimates of orbits and masses b. complete composition c. precise mas

LenKa [72]

<em>The correct option is </em><em>A</em>. The information we know about the known exoplanets is estimates of orbits and masses.

<h3>What is exoplanets?</h3>

An exoplanet or extrasolar planet is a planet outside the Solar System.

In other words, exoplanet is any planet beyond our solar system.

<h3>Characteristics of exoplanets</h3>

exoplanets are known for the following characteristics;

they are usually hot
they can orbit their stars so tightly that a “year” lasts only a few days
they can orbit two suns at once

Thus, the information we know about the known exoplanets is estimates of orbits and masses.

Learn more about exoplanets here: brainly.com/question/1514493

#SPJ1

5 0

2 years ago