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3 years ago

What is the net force of a 10 kg box with a velocity of 2 meters a second?

Physics

2 answers:

Amiraneli [1.4K]3 years ago

8 0

If the velocity is not changing, then the net force acting on the box is zero.

Law Incorporation [45]3 years ago

7 0

Answer:

F=?

Explanation:

m=10kg

v=2ms-1

t=1s

F=mv/t

F=[10][2]/[1]

F=20N

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A young man exerted a force of 9,000 N on a stalled car but was unable to move it. How much work was done?

olasank [31]

W=F*s
W=9000*0
W=0
W:Work
F:Force
s:Distance

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3 years ago

Which of the following mathematical operations are and are not not allowed on two quantities with different unit dimensions?

Katyanochek1 [597]

The following mathematical operations are and are not allowed on two quantities with different unit dimensions are C) Allowed : Multiplication, Division , Not Allowed : Addition, Subtraction, Equality

To answer the question, we have to know what mathematical operations are.

<h3>What are Mathematical operations?</h3>

Mathematical operations are operations which are performed to change the value of a variable. The arithmetic mathematical operations we have are

addition,
subtraction,
multiplication,
subtraction and
equality which shows the relationship between two quantities.

Now, for two quantities with different unit dimensions, addition, subtraction and equality are not allowed because these mathematical operations require the quantities to be in the same unit dimensions

Also, for two different quantities with differnt unit dimensions, multiplication and division are allowed because these mathematical operations do not require the quantities to be in the same unit dimensions.

So, the mathematical operations that are allowed are multiplication and division while the mathematical operations that are not allowed are addition, subtraction and equality.

So, the following mathematical operations are and are not allowed on two quantities with different unit dimensions are C) Allowed : Multiplication, Division , Not Allowed : Addition, Subtraction, Equality

Learn more about mathematical operations here:

brainly.com/question/26112472

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2 years ago

a hawk flies in a horizontal arc of radius 10.3 m at a constant speed of 4.8 m/s. find its centripetal acceleration. answer in u

n200080 [17]

The hawk’s centripetal acceleration is 2.23 m/s²

The magnitude of the acceleration under new conditions is 2.316 m/s²

radius of the horizontal arc = 10.3 m

the initial constant speed = 4.8 m/s

we know that the centripetal acceleration is given by

$a_{c}$ = $\frac{v^{2} }{r}$

$a_{c}$ = 23.04/10.3

$a_{c}$ = 2.23 m/s²

It continues to fly but now with some tangential acceleration

$a_{t}$ = 0.63 m/s²

therefore the net value of acceleration is given by the resultant of the centripetal acceleration and the tangential acceleration

$a_{net}$ = $\sqrt{a_{c} ^{2} +a_{t} ^{2} }$

$a_{net}$ = $\sqrt{4.97 + 0.396}$

$a_{net}$ = 2.316 m/s²

So the magnitude of net acceleration will become 2.316 m/s².

learn more about acceleration here :

brainly.com/question/11560829

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1 year ago

1. If I dig a 6FT hole how deep is that hole?

iren [92.7K]

Answer:

For the first one its about 25 feet

Explanation:

5 0

3 years ago

Read 2 more answers

A proton, which is the nucleus of a hydrogen atom, can be modeled as a sphere with a diameter of 2.4 fm and a mass of 1.67 10-27

Step2247 [10]

For the answer to the question above asking to d<span>etermine the density of the proton.
</span>Density is mass over volume.

The volume of a sphere is 4πr³/3. r is half the diameter.

So the density would be 2.3×10¹⁷ kg/m³.
I hope my answer helped you. Feel free to ask more questions. Have a nice day!

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4 years ago

Read 2 more answers