For vertical motion, use the following kinematics equation:
H(t) = X + Vt + 0.5At²
H(t) is the height of the ball at any point in time t for t ≥ 0s
X is the initial height
V is the initial vertical velocity
A is the constant vertical acceleration
Given values:
X = 1.4m
V = 0m/s (starting from free fall)
A = -9.81m/s² (downward acceleration due to gravity near the earth's surface)
Plug in these values to get H(t):
H(t) = 1.4 + 0t - 4.905t²
H(t) = 1.4 - 4.905t²
We want to calculate when the ball hits the ground, i.e. find a time t when H(t) = 0m, so let us substitute H(t) = 0 into the equation and solve for t:
1.4 - 4.905t² = 0
4.905t² = 1.4
t² = 0.2854
t = ±0.5342s
Reject t = -0.5342s because this doesn't make sense within the context of the problem (we only let t ≥ 0s for the ball's motion H(t))
t = 0.53s
Answer:
(D)
Explanation:
Given :
l=3.5 m
Resistance can be calculated as :
Resistance of the wire will be 1.1×
ohms
Option D is correct
Answer:
A. The photographer will get to the jeep before the rhinocerous
Explanation:
Δv = Δd/Δt
we can rearrange for time
Δt = Δd/Δv
For the photographer:
Distance is 10m and moves at 6m/s
Δt = 10m/6m/s
Δt = 1.67s
For the rhinocerous
Distance is 16m and moves at 8m/s
Δt = 16m/8m/s
Δt = 2.00s
The distances were to get to the jeep, the photographer makes it to the jeep in a shorter amount of time than the rhino
The answer is 37 cause the two sides squared and added together equals the hypotenuse squared after that you just find the square root of the answer
