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algol [13]
1 year ago
12

2. A car travels 40 kilometers at an average speed of 80 km/h and then travels 40 kilometers at an average speed of 40 km/h. The

average speed of the car for this 80 km trip is:
Physics
1 answer:
VARVARA [1.3K]1 year ago
4 0
53.3 km/h is the average amount of the car trip if 80km
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A 4000-? resistor is connected across a 220-V power source. What current will flow through the resistor?
Varvara68 [4.7K]

Answer:

55 mA

Explanation:

Ohm's law states:

V = IR

where V is voltage, I is current, and R is resistance.

220 V = I (4000 Ω)

I = 0.055 A

I = 55 mA

7 0
3 years ago
A pressure cooker cooks a lot faster than an ordinary pan by maintaining a higher pressure and temperature inside. the lid of a
BlackZzzverrR [31]

Answer:

m=40.816\ gm

Explanation:

Given;

The operational pressure of the cooker, P=10^5\ Pa (gauge)

area of the opening, a=4\ mm^2

  • We know that the gauge pressure is measured with respect to the atmospheric pressure. As the atmospheric pressure acts on all the components of the system being observed so, we only need to counter the gauge pressure.

As the petcock sits on the opening of the cross-section so, it balances the built-in pressure due to its weight.

<u>Hence:</u>

m.g=P\times a

where:

m= mass of the petcock

g= acceleration due to gravity

m\times 9.8=10^5\times 4\times 10^{-6}

m=40.816\ gm

6 0
3 years ago
A car accelerates uniformly from rest at 2.2 m / s^2 for 3.0 s.Calculate the speed of the car at time t = 3.0 s
Alexxx [7]

Answer:

6.6m/s

Explanation:

we know that

v = u + at

= 0+ 2.2*3

=6.6m/s

4 0
4 years ago
A metal ring 4.60 cm in diameter is placed between the north and south poles of large magnets with the plane of its area perpend
telo118 [61]

Answer:

A. Ein = 8.05*10^-4 V/m

B. Clockwise sense

Explanation:

A. the magnitude of the electric field induced in the ring is obtaind by using the following formula:

\int E_{in} \cdot ds=-\frac{d\Phi_B}{dt}            (1)

Ein: induced electric field

ds: differential of a path of the ring

ФB: magnetic flux in the ring

The Ein vector is parallel to ds in the complete ring. Furthermore, the area of the ring is constant, hence, you have in the equation (1):

\int E_{in}ds=E_{in}(2\pi r)=-A\frac{dB}{dt}\\\\E_{in}=-\frac{A}{2\pi r}\frac{dB}{dt}   (2)

dB/dt = -0.280T/s     (it is decreasing)

A: area of the ring = π(r/2)^2= (π/4) r^2

r: radius of the ring = 4.60/2 = 2.30 cm

Then, you replace the values of all variables in the equation (2):

E_{in}=-\frac{(\pi/4)r^2}{2\pi r}\frac{dB}{dt}=\frac{r}{8}\frac{dB}{dt}\\\\E_{in}=-\frac{0.0230m}{8}(-0.280T)=8.05*10^{-4}\frac{V}{m}

hence, the induced electric field is 8.05*10^-4 V/m

B. The induced current in the ring produced a magnetic field that is opposite to the magnetic field of the magnet. The, in this case you have that the induced current is in a clockwise sense.

6 0
4 years ago
how do the retinas of the eyes of night hunting animals differ from the retinas of animals that hunt during the day time
maksim [4K]
Night hunting animals have more rod cells in their retinas which allows them to see better in the dark.
4 0
3 years ago
Read 2 more answers
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