If you move south at 30 m/s for 30 minutes, your displacement is
D = (30 mtr/s) x (30 min) x (60 sec/min)
D = (30 x 30 x 60) (mtr-min-sec/sec-min)
D = 54,000 meters south
D = <em>54 km south</em>
As we know that spring force is given by
here we know that
F = 700 N
also we know that
k = 3500 N/m
now from above equation we will have
now we will have
so here we can say that end of the spring will be compressed by 20 cm
The gravitational acceleration experienced by the bullet due to the earth's gravitational force is approximately equals to 9.81 m/s^2
At maximum point of height, vertical component of velocity equals to zero because it experiences a pause momentarily before coming back down.
Since -acceleration=(Final velocity-initial velocity) divided by time. Taking upwards to be positive, time taken= 10s
Answer: SG = 2.67
Specific gravity of the sand is 2.67
Explanation:
Specific gravity = density of material/density of water
Given;
Mass of sand m = 100g
Volume of sand = volume of water displaced
Vs = 537.5cm^3 - 500 cm^3
Vs = 37.5cm^3
Density of sand = m/Vs = 100g/37.5 cm^3
Ds = 2.67g/cm^3
Density of water Dw = 1.00 g/cm^3
Therefore, the specific gravity of sand is
SG = Ds/Dw
SG = (2.67g/cm^3)/(1.00g/cm^3)
SG = 2.67
Specific gravity of the sand is 2.67
Juan tiene que conducir su auto desde su casa hasta la casa de su tia, y recorre una distancia de 4km,luego debe
