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Black_prince [1.1K]
3 years ago
10

Jerome solves a problem using the law of conservation of momentum. What should Jerome always keep constant for each object after

the objects collide and bounce apart?
Physics
2 answers:
Bezzdna [24]3 years ago
7 0

Answer:

On edg it should be the second one

Explanation:

I took the tst

s2008m [1.1K]3 years ago
6 0

Jerome solves a problem using the law of conservation of momentum. What should Jerome always keep constant for each object after the objects collide and bounce apart?

a-velocity

b-mass

c-momentum

d-direction

Answer:

b. Mass

Explanation:

This question has to do with the principle of the law of conservation of momentum which states that the momentum of a system remains constant if no external force is acting on it.

As the question states, two objects collide with each other and eventually bounce apart, so their momentum may not be conserved but the mass of the objects is constant for each non-relativistic motion. Because of this, the mass of each object prior to the collision would be the same as the mass after the collision.

Therefore, the correct answer is B. Mass.

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A person of mass m will bungee-jump from a bridge over a river where the height from the bridge to the river is h. The bungee co
Likurg_2 [28]

Answer:k_{min}=\frac{18mg}{h}

Explanation:

Given

mass of person is m

Distance between bridge and river is h

chord has an un-stretched length of \frac{2h}{3}

Let spring constant be k

Person will just stop before hitting the river

Conserve energy i.e. Potential Energy of Person is converted in to elastic energy of chord

mgh=\frac{kx^2}{2}

x=h-\frac{2h}{3}=\frac{h}{3}

mgh=\frac{kh^2}{18}

k=\frac{18mg}{h}

Thus k_{min}=\frac{18mg}{h}

5 0
3 years ago
To move a mass you need a force true or false
monitta

Answer: True

Explanation:

A force must be applied to set a stationary object in motion.

4 0
3 years ago
Type the correct answer in the box. What is the resistance of a circuit with a voltage of 10 volts (V) and a current of 5 amps (
harkovskaia [24]

Resistance = Voltage/Current

                   = 10/5

Resistance = 2 ohms

4 0
3 years ago
Read 2 more answers
What was the average speed for the second leg of the trip? help me im stuck
SVEN [57.7K]

Answer:

The average speed on the second leg of the trip is 2 m/s

Explanation:

Notice that the second leg of the trip is from 8 m in the horizontal axis heading to the left to position 4 m. So the velocity is going to be negative and given by the quotient of the change in position (-4 m) divided by the time it took: 2 seconds.

This gives: -4/ 2 m/s = -2 m/s

But the speed is going to be the absolute value of the velocity, that is:

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3 0
3 years ago
A particle starts at the origin and moves away from it in a straight line. After 1.6 seconds, it is 12.8 meters from the origin.
Digiron [165]

Answer:

Average velocity of the particle is-2.4 m/s

Explanation:

Average velocity is defined as the total velocity divided by the total time. It is given  by the equationv_av= \frac{displacement}{(total time taken)}

In the given problem the particle starts from origin, travels 12.8 m and then reverses direction and travels till -9.23 m within a total time of 3.8 seconds.

Displacement is defines as the shortest distance between initial and final point.  

Here displacement = - 9.23 m

total time=3.8 s

v_av=-9.23/3.8=-2.4 m/s

4 0
3 years ago
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