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Ivan
3 years ago
8

What frequency is received by the ambulance after reflecting from a wall near the person watching the oncoming ambulance (as in

the previous problem). The ambulance is moving at 109 km/h and emitting a steady 821-Hz sound from its siren
Physics
1 answer:
Zepler [3.9K]3 years ago
4 0

Answer:

900.48925 Hz

979.9785 Hz

Explanation:

v_a = Relative velocity of ambulance =109\ km/h=\dfrac{109}{3.6}

v_w = Velocity of wall = 0

v = Velocity of sound in air = 343 m/s

From doppler effect we have

f=f'\dfrac{v+v_w}{v-v_a}\\\Rightarrow f=821\dfrac{343+0}{343-\dfrac{109}{3.6}}\\\Rightarrow f=900.48925\ Hz

The frequency of sound is 900.48925 Hz

When the wall acts like a source

f=f'\dfrac{v+v_a}{v-v_w}\\\Rightarrow f=900.48925\dfrac{343+\dfrac{109}{3.6}}{343-0}\\\Rightarrow f=979.9785\ Hz

The frequency of sound is 979.9785 Hz

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Answer:

The energy of one photon is 2.21x10⁻²⁴ J. Multiplied by 10²⁵ is 22.10 J.

         

Explanation:  

The energy (E) of a photon is:

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Where:

h: is the Planck's constant = 6.62x10⁻³⁴ J.s

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E = h\frac{c}{\lambda} = 6.62 \cdot 10^{-34} J.s\frac{3.00\cdot 10^{8} m/s}{8.97 \cdot 10^{-2} m} = 2.21 \cdot 10^{-24} J

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Now, if we multiply the answer by 10²⁵ we have:

E = 2.21 \cdot 10^{-24} J \cdot 10^{25} = 22.10 J

I hope it helps you!

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