Answer:
22600 cm³ (3 s.f.)
Explanation:
Please see the attached picture for the full solution.
Please Help!! I'm timed!!
2 answers:
You might be interested in
Solution :
Given data :
Mass of the merry-go-round, m= 1640 kg
Radius of the merry-go-round, r = 7.50 m
Angular speed, rev/sec
rad/sec
= 5.89 rad/sec
Therefore, force required,
= 427126.9 N
Thus, the net work done for the acceleration is given by :
W = F x r
= 427126.9 x 7.5
= 3,203,451.75 J
The central force acting on the electron as it revolves in a circular orbit is .
The given parameters;
- <em>speed of electron, v = 2.2 x 10⁶ m/s</em>
- <em>radius of the circle, r = 4.63 x 10⁻¹¹ m</em>
<em />
The central force acting on the electron as it revolves in a circular orbit is calculated as follows;
where;
is mass of electron = 9.11 x 10⁻³¹ kg
Thus, the central force acting on the electron as it revolves in a circular orbit is .
Learn more about centripetal force here:brainly.com/question/20905151