Rate law for the given 2nd order reaction is:
Rate = k[a]2
Given data:
rate constant k = 0.150 m-1s-1
initial concentration, [a] = 0.250 M
reaction time, t = 5.00 min = 5.00 min * 60 s/s = 300 s
To determine:
Concentration at time t = 300 s i.e. ![[a]_{t}](https://tex.z-dn.net/?f=%5Ba%5D_%7Bt%7D)
Calculations:
The second order rate equation is:
![1/[a]_{t} = kt +1/[a]](https://tex.z-dn.net/?f=1%2F%5Ba%5D_%7Bt%7D%20%3D%20kt%20%2B1%2F%5Ba%5D)
substituting for k,t and [a] we get:
1/[a]t = 0.150 M-1s-1 * 300 s + 1/[0.250]M
1/[a]t = 49 M-1
[a]t = 1/49 M-1 = 0.0204 M
Hence the concentration of 'a' after t = 5min is 0.020 M
Answer: 40mm
Explanation:
You would multiply 4.0 by 10.
Answer:
0.20 mol's
Explanation:
1.675 L = 1.675 dm^3
moles = V/(conc):
moles = 1.675/(8.5)
moles = 0.1970... --> 0.20
There are more oxygen atoms in the reactants while there are less oxygen atoms in the product.
Both sides of the equation is supposed to be balanced for a balanced equation. If any one of them isn't balanced, the equation remains unbalanced.
The main reason why the reaction above can not be balanced is:
This chemical reaction SO2 + H2O -> H2SO2 is not correctly written.
It must be: SO2 + H2O -> H2SO3
<em>hope this helps....</em>
<span>The density of a material = mass/ volume
From the question, volume = 6 cm^3. Since the density = 8.9 g/cm^3
We have that 8.9 = mass/ 6
So mass = 8.9 * 6 = 53.4
So it follows that our mass = 53.4g. Hence option D which is 53g.</span>
