Mass of iron chloride (FeCl₂) : 22.68 g
<h3>Further explanation</h3>
Proust stated the Comparative Law that compounds are formed from elements with the same Mass Comparison so that the compound has a fixed composition of elements
In the same compound, although from different sources and formed by different processes, it will still have the same composition/comparison
With this law, we can calculate how many grams an element is needed to make a compound with a certain mass, as desired
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The iron ions in 50 g mixture :
The answer is b.low frequency,high energy
<span>One theory that explains why scientific theories grow stronger over time is because more scientists study and work on the theory. Over time as the theory is studied in greater depth it becomes more accepted.</span>
First put everything into the same measurements.
111 km = 111km
42mpg = 67.592kpg
1 U.K. Gallon = 4.546 liters
67.592/4.546 = 14.8684557853
42mpg = 14.87kpl (kilometers per liter)
1.10 euros/liter = 1.10 euros/liter
If you drive 111 km a day and go 14.87 km a liter, divide 111 by 14.87 to get about 7.46, which is how many liters you will use a day. Multiply the price, 1.10 euros, by the number of liters, 7.46, to get the daily price of gas, which is about 8.206 a day. Multiply by 7 (num of days in week) to get about 57.44
It cost about 57.44 euros for one week of gas.
I hope I'm not too late! And hopefully that is right! No guarantees lol
a) Volume percent
Formula: % v/v = [volume solute / volume solution] * 100
Just to make it easy take a base of 50 volume parts of ethylen glycol and 50 volume parts of water to make 100 volumes of mixture (this assumpion will be valid for all the questions):
% v/v =[ 50 ml ethyleneglycol] / [100 ml mixture] * 100 = 50%
Answer: 50% v/v
b) Mass percent
% m/m = [mass ethylene glycol / mass solution] * 100
mass ethylene glycol = 50 ml * 1.114 g/ ml = 55.7 g
mass of mixture = 100 ml * 1.07 g/ml = 107 g
% m/m = [55.7 / 107 g] * 100 = 52.06 %
Answer: 52.06%
c) Molarity
M = number of moles of solute / liters of solution
number of moles of solute = mass in grams / molar mass
number of moles of ehtylene glycol = 55.7 g / 62.07 g/mol = 0.8974 mol
liters of solution = 0.1 liter
M = 0.8974 mol / 0.1 liter = 8.974 M
Answer: 8.974 M
d) Molality
m = number of moles of solute / kg of solvent
number of moles of ethylen glycol = 0.8974 mol
mass of water = 50 ml * 1 g/ml = 50 g = 0.05 kg
m = 0.8974 mol / 0.05 kg = 17.95 m
Answer: 17.95 m
e) mole fraction
mole fraction = [number of moles of solute] / [number of moles of mixture] * 100
number of moles of ethylen glycol = 0.8974 mol
number of moles of water = 50 g / 18.01 g /mol = 2.776 mol
mole fraction = 0.8974 mol / [0.8974 mol + 2.776 mol] = 0.244
Answer: 0.244
