Answer:
Biggest Radii V²⁺ > V³⁺ > V⁴⁺ > V⁵⁺ Smallest Radii
General Formulas and Concepts:
- Periodic Trends: Atomic/Ionic Radii
- Coulomb's Law
Explanation:
The Periodic Trend for Atomic Radii is down and to the left. Therefore, the element with the largest radius would be in the bottom left corner of the Periodic Table.
Anions will always have a bigger radii than the parent radii. When we add e⁻ to the element, we are increasing the e⁻/e⁻ repulsions. This will cause e⁻ to repel themselves more and thus create more space, increasing the radii size.
Cations will always have smaller radii than the parent radii. When we remove e⁻ from the element, we are decreasing e⁻/e⁻ repulsions. Since there are less e⁻, there is no need for more space and thus decreases the radii size.
Since Cations are smaller than the parent radii, the more e⁻ we remove, the smaller it will become.
Therefore, the least removed e⁻ Vanadium would be the largest and the most removed e⁻ Vanadium would be the smallest.
<u>Answer</u>
79 ml
<u>Explanation</u>
You have 237 237 ml of ammonia, whose strength is 100%.
If you want to make it 75%, then;
let 75% ⇒ 237 ml of ammonia and
25% ⇒ x ml of water.
∴ x = (25% ×237) / 75%
= 5,925/75
= 79 ml of water.
The desirable soil pH for corn ranges from 5.8 to 7.0.
Answer:
Theoretical yield of sodium chloride = 14.04 g
Explanation:
Given data:
Mass of sodium bromide = 25 g
Theoretical yield of sodium chloride = ?
Solution:
Chemical equation:
NaBr + KCl → NaCl + KBr
Number of moles sodium bromide:
Number of moles = Mass /molar mass
Number of moles = 25.0 g / 102.9 g/mol
Number of moles = 0.24 mol
Now we will compare the moles of NaCl with NaBr .
NaBr : NaCl
1 : 1
0.24 : 0.24
Theoretical yield of sodium chloride:
Mass = moles × molar mass
Mass = 0.24 mol × 58.5 g/mol
Mass = 14.04 g
