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4 years ago

9

Write the integer that represents the situation. The temperature was 8degrees°F. It dropped so that the temperature was 0 degree

s°F. ___degrees°F represents the change in temperature.

2 answers:

Bezzdna [24]4 years ago

7 0

8 is the integer that represents this situation.

vampirchik [111]4 years ago

5 0

Answer:

8

Step-by-step explanation:

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Answer:

B, D

Step-by-step explanation:

36/40 simplified is 9/10

9/10 x 2 = 18/20

I hope this helps!

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Answer:

Step-by-step explanation:

I suppose the expression is this $a^2+9a+8.$

We can factor out this expression ( Remember, find two numbers that the sum is 9 and the product is 8. The numbers are 8 and 1)

$a^2+9a+8=(a+1)(a+8)$

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The nth term of a sequence is 3n2/2

AlekseyPX

Answer:17th term I think

Step-by-step explanation:

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3 years ago

An ice cube is melting, and the lengths of its sides are decreasing at a rate of 0.8 millimeters per minute At what rate is the

julia-pushkina [17]

Answer:

The rate of decrease is: $43.2mm^3/min$

Step-by-step explanation:

Given

$l = 18mm$

$\frac{dl}{dt} = -0.8mm/min$ ---- We used minus because the rate is decreasing

Required

Rate of decrease when: $l = 18mm$

The volume of the cube is:

$V = l^3$

Differentiate

$\frac{dV}{dl} = 3l^2$

Make dV the subject

$dV = 3l^2 \cdot dl$

Divide both sides by dt

$\frac{dV}{dt} = 3l^2 \cdot \frac{dl}{dt}$

Given that: $l = 18mm$ and $\frac{dl}{dt} = -0.8mm/min$

$\frac{dV}{dt} = 3 * (18mm)^2 * (-0.8mm/min)$

$\frac{dV}{dt} = 3 * 18 *-0.8mm^3/min$

$\frac{dV}{dt} = -43.2mm^3/min$

<em>Hence, the rate of decrease is: 43.2mm^3/min</em>

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Answer:

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