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Taya2010 [7]
4 years ago
5

Will reward brainliest !!!

Chemistry
2 answers:
Anna [14]4 years ago
8 0
The best answer choice here would be 'Combination'
stiv31 [10]4 years ago
7 0

Answer:

The answer is B. combination

Explanation:

Well honestly its the only one that fits and makes sense, you can try saying the sentence with each of the words and see which fits the best.

hope this helped!

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if oil spills continue, all of the following should be expected except death of aquatic life. polluted groundwater. decreased so
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How many unpaired electrons are present in a ground-state atom from each of the following groups?
musickatia [10]

For 7A(17) :

Electronic configuration ns^2 np^5

So, there are 5 unpaired electrons present in group 7A(17).

<h3>What are Unpaired Electrons?</h3>
  • An unpaired electron is an electron that doesn't form part of an electron pair when it occupies an atom's orbital in chemistry.
  • Each of an atom's three atomic orbitals, designated by the quantum numbers n, l, and m, has the capacity to hold a pair of two electrons with opposing spins.
  • Unpaired electrons are extremely uncommon in chemistry because an object carrying an unpaired electron is typically quite reactive. This is because the production of electron pairs, whether in the form of a chemical bond or as a lone pair, is frequently energetically advantageous.
  • They play a crucial role in describing reaction pathways even though they normally only appear momentarily during a reaction on a thing called a radical in organic chemistry.

To learn more about unpaired electrons with the given link

brainly.com/question/14356000

#SPJ4

6 0
2 years ago
Draw an electrolytic cell in which Mn2+ is reduced to Mn and Sn is oxidized to Sn2+. (Assume standard conditions).
babunello [35]

Answer:

-1.05 V

Explanation:

A detailed diagram of the setup as required in the question is shown in the image attached to this answer. The electrolytes chosen are SnCl2 for the anode half cell and MnCl2 for the cathode half cell. Tin rod and manganese rod are used as the anode and cathode materials respectively. Electrons flow from anode to cathode as indicated. The battery connected to the set up drives this non spontaneous electrolytic process.

Oxidation half equation;

Sn(s) ------> Sn^2+(aq) + 2e

Reduction half equation:

Mn^2+(aq) + 2e ----> Mn(s)

Cell voltage= E°cathode - E°anode

E°cathode= -1.19V

E°anode= -0.14 V

Cell voltage= -1.19 V - (-0.14V)

Cell voltage= -1.05 V

8 0
3 years ago
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