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Lady bird [3.3K]
2 years ago
5

Under which temperature and pressure would helium behave most like an ideal gas? A) 40 K and 0.2 atm B) 40 K and 5.0 atm C) 600

K and 0.2 atm D) 600 K and 5.0 atm
Chemistry
2 answers:
Vitek1552 [10]2 years ago
8 0

Answer:

btc all i asked for was for u to help me

Explanation:

nadya68 [22]2 years ago
5 0

Answer:

This is a tough one >_<

Explanation:

I think the answer is b.

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Convert 6.33×10−6 cg to nanograms.
tensa zangetsu [6.8K]
5.73e+8 hope this help
5 0
3 years ago
Hi, can someone help me with chemistry
Dominik [7]
Idk look it up on another website
6 0
3 years ago
4.Identify each substance in the following word equation as a reactant or a product
Anastaziya [24]

Explanation:

4.                 limestone heat lime + carbon dioxide

The reactants in this expression above is limestone

The products of the reaction is carbon dioxide and lime

Reactant is the species that gives the product and it is usually found on the left hand side of the expression.

The product is the substance on the right hand side of the expression that forms through the experiment.

Heat is used to facilitate the reaction.

5. An exothermic reaction is a reaction in which heat is given off.

An endothermic reaction is a reaction in which heat is absorbed in the process.

An exothermic reaction is always warmer after the reaction whereas an endothermic reaction is colder at the end of the reaction.

5 0
3 years ago
A 215-g sample of copper metal at some temperature is added to 26.6 g of water. The initial water temperature is 22.22 oC, and t
andrezito [222]

The initial temperature of the copper metal was 27.38 degrees.

Explanation:

Data given:

mass of the copper metal sample = 215 gram

mass of water = 26.6 grams

Initial temperature of water = 22.22 Degrees

Final temperature of water = 24.44 degrees

Specific heat capacity of water = 0.385 J/g°C

initial temperature of copper material , Ti=?

specific heat capacity of water = 4.186 joule/gram °C

from the principle of:

heat lost = heat gained

heat gained by water is given by:

q water = mcΔT

Putting the values in the equation:

qwater = 26.6 x 4.186 x (2.22)

qwater = 247.19 J

qcopper = 215 x 0.385 x (Ti-24.4)

              = 82.77Ti - 2019.71

Now heat lost by metal = heat gained by water

82.77Ti - 2019.71 = 247.19

Ti = 27.38 degrees

8 0
3 years ago
How many moles are in 458 grams of na2so4
shtirl [24]

# moles = mass (g) / Mr (relative atomic mass)

# moles = 458 / ((23*2)+32+(16*4)

# moles= 458 /  142 = 3.2253521126760...

= 3.23 moles

5 0
3 years ago
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