<u>Given:</u>
Mass of Ag = 1.67 g
Mass of Cl = 2.21 g
Heat evolved = 1.96 kJ
<u>To determine:</u>
The enthalpy of formation of AgCl(s)
<u>Explanation:</u>
The reaction is:
2Ag(s) + Cl2(g) → 2AgCl(s)
Calculate the moles of Ag and Cl from the given masses
Atomic mass of Ag = 108 g/mol
# moles of Ag = 1.67/108 = 0.0155 moles
Atomic mass of Cl = 35 g/mol
# moles of Cl = 2.21/35 = 0.0631 moles
Since moles of Ag << moles of Cl, silver is the limiting reagent.
Based on reaction stoichiometry: # moles of AgCl formed = 0.0155 moles
Enthalpy of formation of AgCl = 1.96 kJ/0.0155 moles = 126.5 kJ/mol
Ans: Formation enthalpy = 126.5 kJ/mol
<span>Good Morning!
</span><span>reactants
</span><span>
Substances that make up a chemical reaction, in order to be combined or separated, are called reagents. These reagents can be of the most varied types and origins. The result of this reaction is called a "product."
Hugs</span>
Which way can heat never flow?
The wrong answer is a,c,d
The correct answer is b. Cold to Hot
(D) At equilibrium, the concentration of the products will be much higher than the concentration of the reactants.
Answer:
ExplanatioFirst let us compute for the molar mass of Mg(OH)2.
molar mass = 24.3 + 2 (16) + 2(1.0)
molar mass = 58.3 g/mol
So the mass is then:
mass = 3.2 mol * (58.3 g/mol)
mass = 186.56 gramsn:
