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Mkey [24]
3 years ago
8

Matt is touring a nation in which coins are issued in two amounts, 2¢ and 5¢, which are made of iron and copper, respectively. I

f Matt has ten iron coins and ten copper coins, how many different sums from 1¢ to 70¢ can he make with a combination of his coins?
Chemistry
1 answer:
MariettaO [177]3 years ago
7 0

Answer:

It can be made 66 combinations.

Explanation:

Total amount of possibilities= 10×5¢+10×2¢=70¢

The first combination 1¢ cannot be made because 2¢ is not divisible.

The second combination is 2¢. (Possible)

The third combination 3¢ cannot be made for the same reason.

There are no possible combinations for 1¢ and 3¢.

The same happens with 67 and 69.

For example:

66¢= 10×5¢+8×2¢

Next combination will be:

68¢= 10×5¢+9×2¢

And finally:

70¢= 10×5¢+10×2¢

So there are 4 combinations that are not possible.

The total amount of possible combinations are:

70-4=66 combinations

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Answer: The molar mass of the gas is 31.6 g/mol

Explanation:

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PV=nRT

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R = gas constant =0.0821Latm/Kmol

T =temperature =27.0^0C=(27.0+273)K=300K

n=\frac{PV}{RT}

n=\frac{3.0atm\times 25.0L}{0.0821 L atm/K mol\times 300K}=3.04moles

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Read 2 more answers
Can you check this for me?
Aliun [14]
Hi, your answer is correct.
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