Answer:
1 mole
Explanation:
Given parameters:
Mass of sulfur = 32.066g
Unknown:
Number of moles of sulfur = ?
Solution:
The number of moles of sulfur can be determined using;
Number of moles =
Molar mass of sulfur = 32g/mol
Number of moles = = 1 mole
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To find the empirical formula you would first need to find the moles of each element:
58.8g/ 12.0g = 4.9 mol C
9.9g/ 1.0g = 9.9 mol H
31.4g/ 16.0g = 1.96 O
Then you divide by the smallest number of moles of each:
4.9/1.96 = 2.5
9.9/1.96 = 6
1.96/1.96 = 1
Since there is 2.5, you find the least number that makes each moles a whole number which is 2.
So the empirical formula is C5H12O2.
Answer:
C
Explanation
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Answer:
D. 77.5.
Explanation:
- From the balanced equation: <em>CaCl₂ + 2AgNO₃ → 2AgCl + Ca(NO₃)₂</em>
- It is clear that 1.0 mole of CaCl₂ reacts with 2.0 moles of AgNO₃ to produce 2.0 moles of AgCl and 1.0 mole of Ca(NO₃)₂.
- The no. of moles of reacted (30.0 g) CaCl₂ = mass / molar mass = (30.0 g) / (110.98 g/mol) = 0.27 mol.
<em><u>Using cross multiplication:</u></em>
1.0 mole of CaCl₂ produces → 2.0 moles of AgCl, from the stichiometry.
0.27 mol of CaCl₂ produces → ??? moles of AgCl.
∴ The no. of moles of the produced AgCl = (2.0 mol)(0.27 mol) / (1.0 mol) = 0.54 mol.
∴ The mass of the produced AgCl = no. of moles x molar mass = (0.54 mol)(143.32 g/mol) = 77.48 g ≅ 77.5 g.