i may be wrong but Use the normal boiling points: propane, C3H8, –42.1˚C; butane, C4H10, –0.5˚C; pentane, C5H12, 36.1˚C; hexane, C6H14, 68.7˚C; heptane, C7H16, 98.4˚C; to estimate the normal boiling point of octane, C8H18.
1. A mixture of ammonium chloride, sand, and zinc chloride should be separated by sublimation.
2. A mixture of zinc chloride and silver chloride should be separated through crystallization.
<h3>What is a separation technique?</h3>
A separation technique can be defined as a technique that is typically used to separate or convert two (2) or more mixture and solution of chemical substances into distinct product such as chemical compounds or elements.
<h3>The types of
separation technique.</h3>
In Chemistry, there are various types of separation technique used for the separation of mixtures or solutions and these include:
In this scenario, the most effective and efficient means to separate a mixture of ammonium chloride, sand, and zinc chloride is by sublimation from solid to gas state.
On the other hand, the best means to separate a mixture of zinc chloride and silver chloride is through crystallization.
Read more on crystallization here: brainly.com/question/4980962
Hi the answer is actually B
Answer:
H2C2O4.2H20 → CO2 + CO + H2O
Explanation:
Oxalic acid crystals are nothing but dehydrated oxalic acid (H2C2O4 . 2H2O).
On heating, the water of crystallization is lost first. Then, the dehydrated oxalic acid decomposes into carbon dioxide(CO2), carbon monoxide(CO) and water(H2O).
Equations involved :
H2C2O4 . 2H2O → H2C2O4 + 2H2O
H2C2O4 → CO2 + HCOOH (FORMIC ACID)
HCOOH → CO + H2O
Overall equation : H2C2O4.2H20 → CO2 + CO + H2O
Molecules with a plane of symmetry between the chiral centers are achiral and meso. From the given molecules (Picture attached) only (A) compound 1 is meso.
When compounds possess a plane of symmetry between the chiral centers they are called achiral or meso compounds. Among the given compounds (A) compound 1 have a plane of symmetry. So we can say compound one is a meso or achiral compound. Compounds two, three, and four have no plane of symmetry, as you can see in the structures attached. So all other compounds (compound 2, compound 3, and compound 4) except compound one are not meso or achiral.
You can also learn about meso compounds from the following question:
brainly.com/question/29022658
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