CaBr2(aq) is an ionic compound which will have the releasing of 2 Br⁻ ions ions in water for every molecule of CaBr2 that dissolves.
CaBr2(s) --> Ca+(aq) + 2 Br⁻(aq)
[Br⁻] = 0.17 mol CaBr2/1L × 2 mol Br⁻ / 1 mol CaBr2 = 0.34 M
The answer to this question is [Br⁻] = 0.34 M
Answer:
Alkenes, Markovnikov's, Alkenes, Alkyl halides, and less.
Explanation:
Alkenes must undergo addition because they have easily broken π bonds.
Markovnikov's rule states in the addition of HX to an unsymmetrical alkene, the H atom bonds to the less substituted carbon atom.
Alkenes are unsaturated hydrocarbons because they have fewer than the maximum number of hydrogen atoms per carbon.
Alkyl halides have good leaving groups and therefore readily undergo substitution and elimination reactions.
In hydroboration, the boron atom bonds to the less substituted carbon.
I'd say it's suspension, but I'm not 100% sure...
It increases across a period and decreases down a group. A good way to remember this is that fluorine is the most electronegative atom, and it's to the top right of the table.
When reversing a given reaction, we simply change the sign of the standard enthalpy change value. Therefore, the reaction will become:
H₂O → H₂ + 0.5O₂, ΔH = 286kJ
This is because if a certain amount of energy is released when a reaction occurs, the same amount of energy must be supplied for the reaction to occur in the reverse direction.
