Answer:
The mass of P₄O₁₀ (s) formed is 471.03 g
Explanation:
4PH₃(g) + 8O₂(g) → P₄O₁₀ (s) + 6H₂O (g)
This is the ballanced equation.
Every 4 moles of phosphine, 1 mol of tetraphosphorus decaoxide is generated.
Moles of PH₃ = Mass PH₃ / Molar mass PH₃
Moles PH₃ = 225 g / 33.9 g/m
Moles PH₃ = 6.63 moles
So the rule of three, will be:
If 4 moles of PH₃ generate 1 mol P₄O₁₀
Then, 6.63 moles of PH₃ generate (6.63 .1)/4 = 1.66 moles
If we want to know the mass:
Moles . Molar mass = mass
Molar mass P₄O₁₀ = 283.88 g/m
1.66m . 283.88 g/m = 471.03 g
