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lakkis [162]
3 years ago
9

I need to someone to explain the whole being of Chemistry. I do not understand a single thing, nothing makes sense to me. Litera

lly, I'm going to fail this class because I do NOT understand a single thing taught to me. Maybe it's because I was mistakenly put into Chemistry Pre AP instead of on level but it's so hard and- I just do not get it.
Chemistry
1 answer:
tankabanditka [31]3 years ago
3 0

Answer:

Explanation:

In Pre-AP Chemistry, the development of models to explain their macroscopic observations is a primary means through which students develop an understanding of the molecular world.

You will be forced to think and apply concepts to new situations, and even derive your own theories from application. This is excellent preparation for the higher levels of thinking required in college.

Chemistry, the science that deals with the properties, composition, and structure of substances (defined as elements and compounds), the transformations they undergo, and the energy that is released or absorbed during these processes.

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A !.!.!.!.!.!!..!.!.!.!.!.!.!.!!.!..!!.!.!.!.!.!.!.!.!.!.!!.!.!.!.!
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Family members on a camping trip decide to make hot cocoa after dinner. They add instant cocoa mix to hot water. What can they d
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Answer:

Your ANSWER:

A.stir the hot cocoa

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Owls do most of their hunting during the night and they have specialized cells in their eyes that provide good night vision. The
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C) They have a large number of rods and small number of cones.
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Manganese dioxide (MnO2(s), Hf = –520.0 kJ) reacts with aluminum to form aluminum oxide (AI2O3(s), Hf = –1699.8 kJ/mol) and mang
Temka [501]

Answer : The enthalpy of the reaction = -1839.6 KJ

Solution : Given,

\Delta (H_{f})_{MnO_{2}} = -520.0 KJ/mole

\Delta (H_{f})_{Al_{2}O_{3}} = -1699.8 KJ/mole

The balanced chemical reaction is,

3MnO_{2}(s)+4Al(s)\rightarrow 2Al_{2}O_{3}(s)+3Mn(s)

Formula used :

\Delta (H_{f})_{reaction}=\sum n(\Delta H_{f})_{product}-\sum n(\Delta H_{f})_{reactant}

\Delta (H_{f})_{reaction}=(2\times \Delta H_{Al_{2}O_{3}(s)}+3\times \Delta H_{Mn(s)} )-(3\times \Delta H_{MnO_{2}(s) }+4\times\Delta H_{Al}(s))

We know that the standard enthalpy of formation of the element is equal to Zero.

Therefore, the enthalpy of formation of (Mn) and (Al) is equal to zero.

Now, put all the values in above formula, we get

\Delta (H_{f})_{reaction}=[2moles\times (-1699.8 KJ/mole)}+3moles\times (0\text{ KJ/mole}})]-[(3moles\times(-520.0KJ/mole }+4moles\times(0\text{ KJ/mole})]

                        = (-3399.6) + (1560)

                        = -1839.6 KJ



5 0
3 years ago
The decomposition of SOCl2 is first-order in SOCl2. If the half-life for the reaction is 4.1 hr, how long would it take for the
qaws [65]
4.1 h = 14760 s 

<span>t 1/2 = ln 2 / k </span>

<span>k = rate reaction = 4.97 x 10^-5 </span>

<span>ln 0.045 / 0.36 = - 4.97 x 10^-5 t </span>

<span>2.08 = 4.97 x 10^-5 t </span>

<span>t = 41839.9 s = 11 h 37 min 19 s</span>
3 0
3 years ago
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