Question

PLEASE HELP!!!

Answer 1

Let $X$ be the random variable for the part's diameter, and $Z$ the same variable transformed into one that follows the standard normal distribution. You're looking for the proportion of the parts that lie 2 standard deviations away from the mean, which translates to

$\mathbb P(|X|>15.000+2\times0.030)=\mathbb P(|X|>15.060)=\mathbb P(|Z|>2)$

Recall the empirical rule, which says that approximately 95% of a normal distribution falls within 2 standard deviations of the mean, or $\mathbb P(|Z|$. This means

$\mathbb P(|Z|>2)=1-\mathbb P(|Z|$

So out of 15000 parts, you should expect about 5% of them, or about 750 parts to be rejected.

Answer 2

Answer:

The aanswerr is 750

Step-by-step explanation: