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HACTEHA [7]
3 years ago
5

PLEASE HELP!!!

Mathematics
2 answers:
MatroZZZ [7]3 years ago
8 0
Let X be the random variable for the part's diameter, and Z the same variable transformed into one that follows the standard normal distribution. You're looking for the proportion of the parts that lie 2 standard deviations away from the mean, which translates to

\mathbb P(|X|>15.000+2\times0.030)=\mathbb P(|X|>15.060)=\mathbb P(|Z|>2)

Recall the empirical rule, which says that approximately 95% of a normal distribution falls within 2 standard deviations of the mean, or \mathbb P(|Z|. This means

\mathbb P(|Z|>2)=1-\mathbb P(|Z|

So out of 15000 parts, you should expect about 5% of them, or about 750 parts to be rejected.
Alex3 years ago
5 0

Answer:

The aanswerr is 750

Step-by-step explanation:

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aleksandr82 [10.1K]

Answer:

Isolate the variable by dividing each side by factors that don't contain the variable.

n=5, -5

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2 years ago
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Camilla makes and sells jewelry. She has 8,160 silver beads and 2,880 black beads to make necklaces. Each necklace will contain
Katarina [22]
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3 years ago
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"A rectangle has a height of 5 cm and its base is increasing at a rate" of 3/2 cm/min. When its area is 60 cm2, at what rate is
sukhopar [10]

Answer:

The diagonal is increasing at the rate of 119/104cm/min of the given rectangle.

Step-by-step explanation:

Dimensions of the rectangle

Height = 5cm

Rate of base = 3/2 cm/min

Area = 60cm^2

We know the area of a rectangle of given by = base* Height

b*h = 60

b*5 = 60

b = 12cm

Applying Pythagoras theorem while drawing a diagonal to the rectangle

  b^2 +h^2 =  D^2\\

 5^2 +12^2 = 13^2

so our diagonal will be 13cm  

Upon differentiating the area of the rectangle  we get

b*h = A=60cm^2

using  the chain rule of differentiation

h*db/dt + b*dh/dt  = 0

b*dh/dt = -h*db/dt

12*dh/dt = -5*3/2

dh/dt = -5/8 cm//min

so the height of the rectangle is decreasing at the rate of -5/8cm/min

now we have all the measurements we need

b = 12 , db/dt = 3/2cm/min

h = 5 , dh/dt = -5/8 cm/min

b^2 +h^2  = D^2

Upon differentiating we get

2b*db/dt + 2h*dh/dt = 2D*dD/dt

b*db/dt + h*dh/dt = D*dD/dt

12*3/2 + 5*(-5/8) = 13*dD/dt

18 -25/8 = 13*dD/dt

\frac{144-25}{8} = 13*dD/dt

dD/dt = \frac{119}{104} cm/min

Therefore the diagonal is increasing at the rate of 119/104cm/min of the given rectangle.

6 0
3 years ago
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yarga [219]

Answer:

it is only acute

Step-by-step explanation:

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