Ask question

Ask question

All categories

3 years ago

7

In your own words, describe two conditions that are necessary for an eclipse to occur

1 answer:

Rzqust [24]3 years ago

4 0

1. the Moon must be in line with the Earth and Sun - New Moon for a solar eclipse and Full Moon for a lunar eclipse.2. the Moon must be at one of its nodes. Most of the time the Moon at New or Full passes above or below the Sun because its orbit is tilted relative to the ecliptic. An eclipse can occur only when it is at a node, in other words crossing the ecliptic.

You might be interested in

Periods On the periodic table represent elements

Natalka [10]

Answer:When you look at the periodic table, each row is called a period (Get it? Like PERIODic table.). All of the elements in a period have the same number of atomic orbitals. For example, every element in the top row (the first period) has one orbital for its electrons.

Explanation:

7 0

3 years ago

If 45.0 mL of ethanol (density = 0.789 g/mL) initially at 8.0 ∘C is mixed with 45.0 mL of water (density = 1.0 g/mL) initially a

strojnjashka [21]

Answer : The final temperature of the mixture is, $22.14^oC$

Explanation :

First we have to calculate the mass of ethanol and water.

$\text{Mass of ethanol}=\text{Density of ethanol}\times \text{Volume of ethanol}=0.789g/mL\times 45.0mL=35.5g$

and,

$\text{Mass of water}=\text{Density of water}\times \text{Volume of water}=1.0g/mL\times 45.0mL=45.0g$

Now we have to calculate the final temperature of the mixture.

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

$q_1=-q_2$

$m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)$

where,

$c_1$ = specific heat of ethanol = $2.42J/g^oC$

$c_2$ = specific heat of water = $4.18J/g^oC$

$m_1$ = mass of ethanol = 35.5 g

$m_2$ = mass of water = 45.0 g

$T_f$ = final temperature of mixture = ?

$T_1$ = initial temperature of ethanol = $8.0^oC$

$T_2$ = initial temperature of water = $28.6^oC$

Now put all the given values in the above formula, we get:

$35.5g\times 2.42J/g^oC\times (T_f-8.0)^oC=-45.0g\times 4.18J/g^oC\times (T_f-28.6)^oC$

$T_f=22.14^oC$

Therefore, the final temperature of the mixture is, $22.14^oC$

3 0

3 years ago

What happens to metal when rapidly heated then cooled

Anna [14]

Answer:

It is called tempering. Its tensile strength may reduce but it will become more rigid and hard to break compared to the original metal.

Explanation:

( Source : Quora )

4 0

2 years ago

You have a balloon containing 1 L of air at STP in a vacuum chamber. What will the volume of the balloon be when you reduce the

Ipatiy [6.2K]

P1V1/T1=P2V2/T2 P2=1/2 P1 V1=1 T1=298K

1 P1/298= (1/2) P1V2/373 cross P1

1/298=1/2V2/373
1/298=1/V2 746
v2=746/298
V2=2.5L

5 0

3 years ago

28. Which set of coefficients will balance this chemical equation?

Makovka662 [10]

2021 hoped I helped you god bless you

5 0

3 years ago