The correct equilibrium expression would be one that has products over reactants, and to the power of their stoichiometric coefficient. Also, it would not include any liquids or solids.
The equilibrium expression for your balanced reaction is:
![\Large K_c = \sf{\frac{[SO_3]^2_{equil}}{[SO_2]^2_{equil}[O_2]^2_{equil}}](https://tex.z-dn.net/?f=%5CLarge%20K_c%20%3D%20%5Csf%7B%5Cfrac%7B%5BSO_3%5D%5E2_%7Bequil%7D%7D%7B%5BSO_2%5D%5E2_%7Bequil%7D%5BO_2%5D%5E2_%7Bequil%7D%7D)
Answer:
After 28 sec 7.5 grams of Be will be left
Explanation:
Given data:
Total amount of Be = 30 g
Half life of Be = 14 sec
Mass left after 28 sec = ?
Solution:
First of all we will calculate the number of half lives in 28 sec.
Number of half lives = T elapsed / half life
Number of half lives = 28 sec / 14 sec
Number of half lives = 2
AT time zero = 30 g
At first half life = 30 g/2 = 15 g
At second half life = 15 g/ 2 = 7.5 g
So after 28 sec 7.5 grams of Be will be left.
THE MOLECULE HAS A C=C AND AN -OH GROUP, SO IT IS CALLED AN ENE/OL, I.E., AN ENOL. ENOLS CAN BE FORMED ONLY FROM CARBONYL COMPOUNDS WHICH HAVE ALPHA HYDROGENS. THEY CAN BE FORMED BY ACID OR BASE CATALYSIS, AND ONCE FORMED ARE HIGHLY REACTIVE TOWARD ELECTROPHILES, LIKE BROMINE.
