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Vika [28.1K]
2 years ago
13

Which type of community will have more competition than cooperation?

Chemistry
1 answer:
Vedmedyk [2.9K]2 years ago
6 0

Answer:

a 10,00 year-old coral reef ecosystem

You might be interested in
How many grams do 6.534e+24 molecules of phosphoric acid weigh?
fredd [130]

Answer:

1,063 grams H₃PO₄

Explanation:

To find the mass of phosphoric acid (H₃PO₄), you should (1) convert molecules to moles (via Avogadro's number) and then (2) convert moles to grams (via molar mass from periodic table).

Molar Mass (H₃PO₄): 3(1.008 g/mol) + 30.974 g/mol + 4(15.998 g/mol)

Molar Mas (H₃PO₄): 97.99 g/mol

6.534 x 10²⁴ molecules H₃PO₄                       1 mole                         97.99 g
---------------------------------------------  x  -------------------------------------  x  --------------
                                                            6.022 x 10²³ molecules          1 mole

= 1,063 grams H₃PO₄

3 0
2 years ago
Liters of a 2.40 M
kotykmax [81]

Answer:

1.42 L

Explanation:

Step 1:

The following data were obtained from the question :

Molarity of KBr = 2.40 M

Mole of KBr = 3.40 moles

Volume of solution =?

Step 2:

Determination of the volume of the solution.

Molarity of solution is simply the mole of the solute per unit volume the of solution. It is given as :

Molarity = mole /Volume

Volume = mole /Molarity

Volume = 3.4/2.4

Volume = 1.42 L

Therefore, the volume of the solution is 1.42 L

6 0
3 years ago
1. The most basic units of any element are its
baherus [9]

Answer:

The atom

Explanation:

5 0
3 years ago
What is the hydrogen ion concentration, [H+], of a solution with a pH of 5.43?
grigory [225]

Answer: 3.7 x10−6 Mole per dm^3

Explanation:

pH is the negative logarithm of hydrogen ion concentration in a solution.

So, pH = - log(H+)

Since the solution has a pH of 5.43

5.43 = -log(H+)

To get hydrogen ion concentration, find the Antilog of 5.43

(H+) = Antilog (-5.43)

(H+) = 0.000003715

Then, 0.000003715 in standard form becomes 3.7 x10−6 M

Thus, the concentration of hydrogen ion in the solution is 3.7 x10−6 Mole per dm^3

6 0
3 years ago
PLEASE SHOW YOUR WORK!!
Rom4ik [11]

Answer:

6. 355.1 g of Na₂SO₄ can be formed.

7. 313 g of LiNO₃ were needed

Explanation:

<u>Excersise 6</u>.

The reaction is:  2 NaOH + H₂SO₄ --> 2 H₂O + Na₂SO₄

2 moles of sodium hydroxide react with 1 mol of sulfuric acid to produce 2 moles of water and 1 mol of sodium sulfate.

If we were noticed that the acid is in excess, we assume the NaOH as the limiting reactant. Let's convert the mass to moles (mass / molar mass)

200 g / 40 g/mol = 5 moles.

Now we apply a rule of three with the ratio in the reaction, 2:1

2 moles of NaOH produce 1 mol of sodium sulfate.

5 moles of NaOH would produce (5 .1)/2 = 2.5 moles

Let's convert these moles to mass (mol . molar mass)

2.5 mol . 142.06 g/mol = 355.1 g

<u>Excersise 7.</u>

The reaction is:

Pb(SO₄)₂+ 4 LiNO₃ → Pb(NO₃)₄  +  2Li₂SO₄

As we assume that we have an adequate amount of lead (IV) sulfate, the limiting reactant is the lithium nitrate.

Let's convert the mass to moles (mass / molar mass)

250 g / 109.94 g/mol = 2.27 moles

Let's make a rule of three. Ratio is 2:4.

2 moles of lithium sulfate were produced by 4 moles of lithium nitrate

2.27 moles of Li₂SO₄ would have been produced by ( 2.27 .4) / 2 = 4.54 moles.

Let's convert these moles to mass (mol . molar mass)

4.54 mol . 68.94 g/mol = 313 g

5 0
3 years ago
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