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irinina [24]
4 years ago
15

Identify each statement as referring to a series or parallel circuit.

Engineering
1 answer:
jolli1 [7]4 years ago
7 0

Answer:

1. Parallel circuit

2. Parallel circuit

3. Series circuit

4. Series circuit

5. Parallel circuit

6. Parallel circuit

Explanation:

1. In a parallel circuit, there are multiple paths for current to flow. The path each current takes depends on the resistance of the resistors on that path.

2. In a parallel circuit, current splits up into various paths to get the total current through the circuit, the current flow through each resistor is added.

3. In a series circuit the voltage across each resistor is not the same. to get back the total voltage, the voltages across each resistor needs to be added.

4. Series circuits have voltage drops across each resistor. this makes the voltage across each resistor depend on the resistance of the resistor.

5. In parallel circuits voltage is the same across each resistor because they are all connected directly to the same source.

6. In parallel circuits, the power is the same in each resistor of equal resistance since the voltage across each resistor is the same

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Technician A says inspecting the operation of the automatic emergency brake system helps determine whether the spring brakes wil
laila [671]

Answer: Both Technicians

Explanation:

When testing a spring break it is advisable to Step on and off the brake, with the engine off, the parking brake knob is expected to pop out when air pressure falls between 20-40 psi.

Go under the vehicle and pull the spring brakes.

Turn on the engine back and pump the brake pedal down to the floor. To test the spring breaks

8 0
3 years ago
A metal specimen with an original diameter of 0.50 in. and a gauge length of 2.75 in. is tested in tension until a fracture occu
tatiyna

Answer:

Percent Elongation = 52.72%

Percent Reduction in Area = 64%

Explanation:

First we find percent elongation:

Percent Elongation = {Final Gage Length - Initial Gauge Length/Initial Guage Length} x 100%

Percent Elongation = {(4.20 in - 2.75 in)/2.75 in} x 100%

<u>Percent Elongation = 52.72%</u>

Now, for the percent reduction in area:

Percent Reduction in Area = {Final Cross Sectional Area - Initial Cross Sectional Area|/Initial Cross Sectional Area Length} x 100%

Percent Reduction in Area = {π(0.3 in)² - π(0.5 in)²/π(0.5 in)²} x 100%

<u>Percent Reduction in Area = - 64%</u>

here, negative sign shows a decrease in area.

5 0
3 years ago
The top surface of an L = 5­mm­thick anodized aluminum plate is irradiated with G = 1000 W/m2 while being simultaneously exposed
puteri [66]

Answer:

J=1963W/m^2

q_{rad}=963w/m^2

\triangle T= -0.378k/s

Explanation:

From the question we are told that:

L=5mm => 5*10^{-3}\\Irradiation G=1000W/m^2\\h=50W/m^2\\T_{infinity} = 25C.\\Plate\ temperature\ T_p= 400 K\\\alpha=0.14\\E=0.76

at Temp=400K

E=2702kg/m^2,c=949J/kgk

Generally the equation for Radiosity is mathematically given by

J=eG+\in E_p

J=(1-\alpha)G+\in \sigma T^4

J=(1-0.14)1000+0.76 (5.67*10^_{8}) (400)^4

J=1963W/m^2

Generally the equation for net radiation heat flux q_{rad} is mathematically given by

q_{rad}=J-G\\q_{rad}=1963-1000

q_{rad}=963w/m^2

Generally the equation for and the rate of plate temp \triangleT is mathematically given by

\triangle T= -\frac{q_{con} +q_{rad}}{Ecl}

\triangle T= \frac{45(400)-(30+273+963)}{(2702*949*0.005)}

\triangle T= -0.378k/s

6 0
3 years ago
Guys, I need help. Describe carburetion as it applies to the four-stroke engine.
marta [7]

Answer:

(NH4)2Cr2O7→Cr2O3+N2+4H2O

Explanation:

(NH4)2Cr2O7→Cr2O3+N2+4H2O

7 0
3 years ago
What is the definition of a duty cycle?
ira [324]

Answer:

D=\frac{PW}{T}*100

Explanation:

In electrical terms, is the ratio of time in which a load or circuit is ON compared to the time in which the load or circuit is OFF.

The duty cycle or power cycle, is expressed as a percentage of the activation time. For example, a 70% duty cycle is a signal that 70% of the time is activated and the other 30% disabled. Its equation can be expressed as:

D=\frac{PW}{T}*100

Where:

D=Duty\hspace{3}Cycle

PW=Pulse\hspace{3}Active\hspace{3}Time

T=Period\hspace{3}of\hspace{3}the\hspace{3}Signal

Here is a picture that will help you understand these concepts.

5 0
3 years ago
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