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suter [353]
3 years ago
14

PLZZ HELP

Engineering
2 answers:
Anarel [89]3 years ago
6 0
*This is in first person!*

If my daily life was working in the robotics field, then I could use my troubleshooting skills to work on different technologies inside of the robot that aren’t working correctly. So if some of the software inside of the robot wasn’t working, I could narrow down the problem, and fix it. Troubleshooting skills could be very helpful in this field of work.
9966 [12]3 years ago
5 0

Answer:

Could ask a family member to help

Explanation:

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Anything that is made to meet a need or desire is?
slavikrds [6]

Answer:

I think it is process or technology

7 0
2 years ago
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Select four types of engineers who might be involved in the development of a product such as an iPhone.
Bas_tet [7]

Answer:

electrical

computer

mechanical

and manufacturing .... I think

4 0
3 years ago
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What is the rated power output in ( kw) of a 8 pole motor designed to an IEC 180L motor frame ?<br>​
ra1l [238]

Answer:

P=11 kW

Explanation:

Given that

Number of poles= 8

I.E.C. 180L motor frame

From data book , for 8 poles motor at 50 Hz

Speed = 730 rpm

Power factor = 0.75

Efficiency at 100 % load= 89.3 %

Efficiency at 50 % load= 89.1 %

Output power = 11 kW

Therefore the rated output power of 8 poles motor will be 11 kW. Thus the answer will be 11 kW.

P=11 kW

4 0
3 years ago
3. (a) (5 points) Suppose N packets arrive simultaneously to a link at which no packets are currently being transmitted or queue
Bezzdna [24]

Answer:

(N-1) × (L/2R) = (N-1)/2

Explanation:

let L is length of packet

R is rate

N is number of packets

then

first packet arrived with 0 delay

Second packet arrived at = L/R

Third packet arrived at = 2L/R

Nth packet arrived at = (n-1)L/R

Total queuing delay = L/R + 2L/R + ... + (n - 1)L/R = L(n - 1)/2R

Now

L / R = (1000) / (10^6 ) s = 1 ms

L/2R = 0.5 ms

average queuing delay for N packets = (N-1) * (L/2R) = (N-1)/2

the average queuing delay of a packet = 0 ( put N=1)

4 0
3 years ago
Calculate the factor of safety against bending failure of a gear with a given tooth bending stress of 117MPa and a corrected ben
Deffense [45]

Answer:

3

Explanation:

Bending stress = 117 MPa

Yield stress = 354 MPa

Factor of safety is defined as the ratio of yield stress to the allowable stress (tensile, compressive or bending) of a given material

FS= \frac{\text{Yield stress}}{\text{Allowable stress}}\\\Rightarrow FS=\frac{354}{117}\\\Rightarrow FS=3.025

So, factor of safety is almost equal to 3.

3 0
3 years ago
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