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suter [353]
3 years ago
14

PLZZ HELP

Engineering
2 answers:
Anarel [89]3 years ago
6 0
*This is in first person!*

If my daily life was working in the robotics field, then I could use my troubleshooting skills to work on different technologies inside of the robot that aren’t working correctly. So if some of the software inside of the robot wasn’t working, I could narrow down the problem, and fix it. Troubleshooting skills could be very helpful in this field of work.
9966 [12]3 years ago
5 0

Answer:

Could ask a family member to help

Explanation:

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In normal operation, a paper mill generates excess steam at 20 bar and 400◦C. It is planned to use this steam as the feed to a t
Keith_Richards [23]

Answer:

The maximum power that can be generated is 127.788 kW

Explanation:

Using the steam table

Enthalpy at 20 bar = 2799 kJ/kg

Enthalpy at 2 bar = 2707 kJ/kg

Change in enthalpy = 2799 - 2707 = 92 kJ/kg

Mass flow rate of steam = 5000 kg/hr = 5000 kJ/hr × 1 hr/3600 s = 1.389 kg/s

Maximum power generated = change in enthalpy × mass flow rate = 92 kJ/kg × 1.389 kg/s = 127.788 kJ/s = 127.788 kW

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3 years ago
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Answer:

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b.) The problem becomes easier to solve if you draw out the circuit. Since potential at Q is 0, then Q is at ground. So voltage across V_MQ is the same as potential at V_M.

c.) Same process as part b. Draw out the circuit and you'll see that the potential a point V_N is the same as the voltage across V_NP added with the 2V from the other box.

Honestly, these things take practice to get used to. It's really hard to explain this.

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