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elena-s [515]
3 years ago
11

Why, based on what you learned in the module, might an institution like a university choose to use cast, steel-reinforced concre

te as a structural material for a new, important building, rather than wood or stone?
Physics
1 answer:
emmasim [6.3K]3 years ago
5 0

Answer:

based on what I have learnt about structural materials I think steel-reinforsed concrete is the best compared to other forms of materials for buildings

Explanation:

The reasons being that

  1.  Steel is a ductile material as compared to the brittle nature of concrete, thus stopping any sudden failure. And steel can take in tension force which concrete is particularly weak in.

   2. Steel as a material has very good bonding strength with concrete, which helps them start a nice casual conversation, connect and then hold each other in place and not exist as separate entities forced to stay at one place.

   3. The  Modulus of Rigidity remains same for tension and compression, in case of steel.

   4. The steel is always recyclable. so no wastages

   5. Thermal Expansion Coefficient of both steel and concrete is same, coming to an approximate 12*(10)^(-6)/°C. This facilitates saving their relationship through the summers and winters, never having to go through the pain of breakups.

   with all these properties the building could last for 1000 years

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https://doubtnut.app.link/FnsNC80Dccb

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4 years ago
Red light of wavelength 630 nm passes through two slits and then onto a screen that is 1.3 m from the slits. The center of the 3
frozen [14]

Answer:

a) f = 4.76 10¹⁴ Hz, b) d = 2.73 10⁻⁴ m, c) θ = 6.923 10⁻³ rad

Explanation:

a) In this problem the frequency of light is asked, let's use the relationship between the speed of the wave, its wavelength and its frequency

           c = λ f

           f = c /λ

           f = \frac{3 \ 10^8}{630 \ 10^{-9}}

           f = 4.76 10¹⁴ Hz

b) slit separation (d)

the expression for the constructive interference of the double-slit experiment is

          d sin  θ = m λ

let's use trigonometry

          tan θ = y / L

          tan θ = \frac{sin \theta}{cos \theta}

in general the angles are small, so we can approximate

          tan θ = sin θ

          tan θ = y/L

we substitute

          d y / L = m λ

          d = m L λ / y

we calculate

          d = 3  1.3  630 10⁻⁹ /0.90 10⁻²

          d = 2.73 10⁻⁴ m

c) the angle

           tan θ = y / L

           θ = tan⁻¹ y / L

           θ = tan⁻¹ 0.9 10⁻² / 1.3

           θ = tan⁻¹ 6,923 10⁻³

let's find the angle in radians

           θ = 6.923 10⁻³ rad

   

4 0
3 years ago
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