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elena-s [515]
3 years ago
11

Why, based on what you learned in the module, might an institution like a university choose to use cast, steel-reinforced concre

te as a structural material for a new, important building, rather than wood or stone?
Physics
1 answer:
emmasim [6.3K]3 years ago
5 0

Answer:

based on what I have learnt about structural materials I think steel-reinforsed concrete is the best compared to other forms of materials for buildings

Explanation:

The reasons being that

  1.  Steel is a ductile material as compared to the brittle nature of concrete, thus stopping any sudden failure. And steel can take in tension force which concrete is particularly weak in.

   2. Steel as a material has very good bonding strength with concrete, which helps them start a nice casual conversation, connect and then hold each other in place and not exist as separate entities forced to stay at one place.

   3. The  Modulus of Rigidity remains same for tension and compression, in case of steel.

   4. The steel is always recyclable. so no wastages

   5. Thermal Expansion Coefficient of both steel and concrete is same, coming to an approximate 12*(10)^(-6)/°C. This facilitates saving their relationship through the summers and winters, never having to go through the pain of breakups.

   with all these properties the building could last for 1000 years

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Below is a metabolic pathway having 3 chemical reactions and 3 enzymes. Enzyme 1 has 2 binding sites--1 for the substrate A and
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Answer:   The correct answer is :  A, B, C, D.  All statements are correct.

Explanation:  This case is called non-competitive inhibition. As a result of the inhibition of the enzyme, there will eventually be less substrate that becomes the final product and this route will be closed. Enzyme 1 has two binding sites.

6 0
3 years ago
Imagine tying a string to a ball and twirling it around you. How is this similar to the moon orbiting the Earth? In this example
Tema [17]
Its similar to the moon orbiting the earth because lets say that the sing is moon and the ball is earth has the "moon" orbits around the "earth" the string ends up tying around the ball till its no more


i think i hope this example helps you somehow srry that i dont know more then that :/
4 0
3 years ago
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When four quadruplets cry simultaneously, how many decibels greater is the sound intensity level than when a single one cries?
Ket [755]

Answer:

Explanation:

Assume that a single baby cries at X db

4 babies crying would be X + 10log₁₀(4) = X + 6 db

8 0
2 years ago
How are volcanoes formed at subduction zones
gavmur [86]

Answer:

magma forming above a subducting plate slowly rise into the overriding crust causing the formation of a volcano

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3 0
3 years ago
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A third wire of the same material has the same length and twice the diameter as the first. How far will it be stretched by the s
leonid [27]

Complete question is;

A force stretches a wire by 0.60 mm. A second wire of the same material has the same cross section and twice the length.

a) How far will it be stretched by the same force?

b) A third wire of the same material has the same length and twice the diameter as the first. How far will it be stretched by the same force?

Answer:

0.15 mm

Explanation:

According to Hooke's Law,

E = Stress(σ)/Strain(ε)

Where E is youngs modulus

Formula for stress is;

Stress(σ) = Force(F)/Area(A)

Formula for strain is;

Strain(ε) = Change in length/original length = (Lf - Li)/Li

We are also told that a second wire of the same material has the same cross section and twice the length.

Thus;

Rearranging Hooke's Law to get the constants on one side, we have;

F/(AE) = ε

Thus from the conditions given;

ε1 = 0.6/Li

ε2 = (Change in length)/(2*Li)

And ε1 = ε2

Thus;

0.6/Li = Change in length/(2*Li)

Li will cancel out and we now have;

Change in length = 2 × 0.6 = 1.2 mm

Finally, we are told A third wire of the same material has the same length and twice the diameter as the first.

Area of a circle;A1 = πd²/4

Now, we are told d is doubled.

Thus, new area of the new circle is;

A2 = π(2d)²/4 = πd²

Rearranging Hooke's Law,we have;

F/A = εE

Since F and E are now constants, we have;

F/E = constant = Aε

Thus;

A1(ε1) = A2(ε2)

A1 = πd²/4

e1 = 0.60/Li

A2 = πd²

e2 = Change in length/Li

Thus;

((πd²/4) × 0.6)/Li = (πd² × Change in length)/ Li

Rearranging, Li and πd² will cancel out to give;

0.6/4 = Change in length

Change in length = 0.15 mm

4 0
2 years ago
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