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elena-s [515]
3 years ago
11

Why, based on what you learned in the module, might an institution like a university choose to use cast, steel-reinforced concre

te as a structural material for a new, important building, rather than wood or stone?
Physics
1 answer:
emmasim [6.3K]3 years ago
5 0

Answer:

based on what I have learnt about structural materials I think steel-reinforsed concrete is the best compared to other forms of materials for buildings

Explanation:

The reasons being that

  1.  Steel is a ductile material as compared to the brittle nature of concrete, thus stopping any sudden failure. And steel can take in tension force which concrete is particularly weak in.

   2. Steel as a material has very good bonding strength with concrete, which helps them start a nice casual conversation, connect and then hold each other in place and not exist as separate entities forced to stay at one place.

   3. The  Modulus of Rigidity remains same for tension and compression, in case of steel.

   4. The steel is always recyclable. so no wastages

   5. Thermal Expansion Coefficient of both steel and concrete is same, coming to an approximate 12*(10)^(-6)/°C. This facilitates saving their relationship through the summers and winters, never having to go through the pain of breakups.

   with all these properties the building could last for 1000 years

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Compressions and rarefactions are characteristic of
Korvikt [17]

Answer:

Of longitudinal waves

Explanation:

Depending on the direction of the oscillation, there are two types of waves:

- Transverse waves: in a transverse wave, the oscillations occur perpendicularly to the direction of propagation of the wave. Examples are electromagnetic waves.

- Longitudinal waves: in a longitudinal wave, the oscillations occur parallel to the direction of propagation of the wave. In such a wave, the oscillations are produced by alternating regions of higher density of particles, called compressions, and regions of lower density of particles, called rarefactions. Examples of longitudinal waves are sound waves.

6 0
3 years ago
The 2.6-kg collar is released from rest at A and slides down the inclined fixed rod in the vertical plane. The coefficient of ki
neonofarm [45]

Answer:

The attached diagram explains the system,

Sum of Fy = 0

N=9.81

N - mgCos60 = 0

F= ukN= (0.53)(9.81) =

F= 5.12 N

So

F.d= 1/2(mv.v) - mgdsin60

-5.12*0.5 = 0.5*v^2 - 2*(9.81)*(0.5*sin60)

(a)  v = 2.436 m/s

For deflection

-F.x = 1/2(mv.v) - mgxsin60 + 1/2 (k*x*x)

by solving for with values of v, m, g, F, k

800x^2 - 11.87 x - 5.938 = 0

by solving the quadratic equation

x = 0.093, -0.079

(b) x = 0.093 m

correct Answer is 0.093m

Explanation:

3 0
3 years ago
Neutron stars, such as the one at the center of the Crab Nebula, have about the same mass as our sun but have a much smaller dia
Crank

Answer:

Wn = 9.14 x 10¹⁷ N

Explanation:

First we need to find our mass. For this purpose we use the following formula:

W = mg

m = W/g

where,

W = Weight = 675 N

g = Acceleration due to gravity on Surface of Earth = 9.8 m/s²

m = Mass = ?

Therefore,

m = (675 N)/(9.8 m/s²)

m = 68.88 kg

Now, we need to find the value of acceleration due to gravity on the surface of Neutron Star. For this purpose we use the following formula:

gn = (G)(Mn)/(Rn)²

where,

gn = acceleration due to gravity on surface of neutron star = ?

G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²

Mn = Mass of Neutron Star = Mass of Sun = 1.99 x 10³⁰ kg

Rn = Radius of neutron Star = 20 km/2 = 10 km = 10000 m

Therefore,

gn = (6.67 x 10⁻¹¹ N.m²/kg²)(1.99 x 10³⁰ kg)/(10000)

gn = 13.27 x 10¹⁵ m/s²

Now, my weight on neutron star will be:

Wn = m(gn)

Wn = (68.88)(13.27 x 10¹⁵ m/s²)

<u>Wn = 9.14 x 10¹⁷ N</u>

3 0
3 years ago
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r-ruslan [8.4K]
I'm pretty sure it's B

I hope that helps 
6 0
3 years ago
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