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elena-s [515]
4 years ago
11

Why, based on what you learned in the module, might an institution like a university choose to use cast, steel-reinforced concre

te as a structural material for a new, important building, rather than wood or stone?
Physics
1 answer:
emmasim [6.3K]4 years ago
5 0

Answer:

based on what I have learnt about structural materials I think steel-reinforsed concrete is the best compared to other forms of materials for buildings

Explanation:

The reasons being that

  1.  Steel is a ductile material as compared to the brittle nature of concrete, thus stopping any sudden failure. And steel can take in tension force which concrete is particularly weak in.

   2. Steel as a material has very good bonding strength with concrete, which helps them start a nice casual conversation, connect and then hold each other in place and not exist as separate entities forced to stay at one place.

   3. The  Modulus of Rigidity remains same for tension and compression, in case of steel.

   4. The steel is always recyclable. so no wastages

   5. Thermal Expansion Coefficient of both steel and concrete is same, coming to an approximate 12*(10)^(-6)/°C. This facilitates saving their relationship through the summers and winters, never having to go through the pain of breakups.

   with all these properties the building could last for 1000 years

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The drinking water needs of an office are met by cooling tab water in a refrigerated water fountain from 23 to 6°C at an average
Ratling [72]

Answer:

The correct option is;

(c) 64W

Explanation:

Here we have the Coefficient Of Performance, COP given by

COP = \frac{Q_{cold}}{W} = 3.1

The heat change from 23° to 6°C for a mass of 10 kg/h which is equivalent to 10/(60×60) kg/s or 2.78 g/s we have

Q_{cold} = m·c·ΔT = 2.78 × 4.18 × (23 - 6) = 197.39 J

Therefore, plugging in the value for  Q_{cold} in the COP equation we get;

COP = \frac{197.39 }{W} = 3.1 which gives

W =  \frac{197.39 }{3.1} = 63.674 \ J

Since we were working with mass flow rate then the power input is the same as the work done per second and the power input to the refrigerator = 63.674 J/s ≈ 64 W.

The power input to the refrigerator is approximately 64 W.

4 0
4 years ago
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A ball is thrown nearly vertically upward from a point near the cornice of a tall building. It just misses the cornice on the wa
vovangra [49]

Answer:

a) 48.5 ft/s

b) 36.5 ft

c) -80.3 ft/s

Explanation:

a)

The equation of motion of the ball is :

y(t) = -16.1 ft/s^2 * t^2 + Vo*t

Where Vo is the initial velocity

If y(5s) = - 160 ft:

-160 ft = -16.1 ft/s^2 * (5 s)^2 + Vo*(5s)

Solving for Vo

Vo  = (16.1*25- 160) ft / 5s = 48.5 ft/s

b)

To answer this question we must first know when the velocity became zero, at this time is when the ball was at its highest point.

v(t) = -32.2 ft/s^2 * t + Vo

t = Vo/32.2ft/s^2 = 1.5 s

And now, the highest point which the ball reached is given by:

y(1.5s) = -16.1 ft/s^2 * (1.5)^2 + Vo*(1.5s)

y(1.5s) = 36.52 ft

c)

We now need the time at which y(t') = -64 ft

-64 = -16.1*t'^2 + 48.5*t'

By means of the quadratic formula, we find that

t' = 4.00498 s ≈ 4 s

And the velocity at t = 4s is:

v(4s) = -32.2 ft/s^2 * 4s +48.5 ft/s = -80.3 ft/s

3 0
4 years ago
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