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kifflom [539]
3 years ago
14

Un coche que lleva una velocidad constante de 90 km/hora durante 2 horas ¿Cuánto espacio recorre?Si encuentra un obstáculo en la

carrera y tiene que parar 10 segundos calcula la aceleración
Physics
1 answer:
Kisachek [45]3 years ago
4 0

Answer:

(i) El coche recorre 180 kilómetros.

(ii) El coche decelera a razón de 2.5 metros por segundo al cuadrado.

Explanation:

El problema se divide en dos partes. La primera es el coche viajando a velocidad constante y la segunda consiste en una decelaración hasta alcanzar el reposo.

Primera parte - Viaje a velocidad constante

La distancia recorrida por el coche se calcula mediante la siguiente ecuación cinemática:

x = v\cdot t (1)

Donde:

x - Distancia recorrida, en kilómetros.

v - Velocidad, en kilómetros por hora.

t - Tiempo, en horas.

Si sabemos que v = 90\,\frac{km}{h} y t = 2\,h, entonces la distancia recorrida por el coche es:

x = v\cdot t

x = 180\,km

El coche recorre 180 kilómetros.

Segunda parte - Deceleración

Asumiendo que la deceleración del coche es constante, se determina mediante la siguiente ecuación cinemática:

a = \frac{v-v_{o}}{t} (2)

Donde:

v_{o} - Velocidad inicial, en metros por segundo.

v - Velocidad final, en metros por segundo.

t - Tiempo, en segundos.

Si sabemos que v_{o} = 25\,\frac{m}{s}, v = 0\,\frac{m}{s} y t = 10\,s, entonces la deceleración experimentada por el coche es:

a = -2.5\,\frac{m}{s^{2}}

El coche decelera a razón de 2.5 metros por segundo al cuadrado.

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