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erica [24]
2 years ago
9

An acetylide anion is more stable than either a vinylic or alkyl anion due to Group of answer choices the greater stability of a

n sp hybrid orbital. the stabilization of the negative charge in orbitals with higher s character. the greater distance of the negative charge from the nucleus of the carbon atom. the larger number of π electrons.
Chemistry
1 answer:
sashaice [31]2 years ago
5 0

Answer:

the stabilization of the negative charge in orbitals with higher s character

Explanation:

Acetylide anion is a carbon anion compound or popularly called carbanion. Now Acetylide anion is sp hybridized. However acetylide anion tends to be more acidic as we move from sp³ to sp, hence acidicity increases, which makes sp to have the highest acidity and become the most  stable.

So, we can conclude that the acetylide anion is more acidic due to the stabilization of the negative charge in orbitals with higher s character and  as the s character increases, acidic nature of acetylide anion also increases.

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Draw a mechanism for the reaction of methylamine with 2-methylpropanoic acid. Draw any necessary curved arrows. Show the product
Nitella [24]

Answer:

See figure 1

Explanation:

On this case we have a <u>base</u> (methylamine) and an <u>acid</u> (2-methyl propanoic acid). When we have an acid and a base an <u>acid-base reaction </u>will take place, on this specific case we will produce an <u>ammonium carboxylate salt.</u>

Now the question is: <u>¿These compounds can react by a nucleophile acyl substitution reaction?</u> in other words <u>¿These compounds can produce an amide? </u>

Due to the nature of the compounds (base and acid), <u>the nucleophile</u> (methylamine) <u>doesn't have the ability to attack the carbon</u> of the carbonyl group due to his basicity. The methylamine will react with the acid-<u>producing a positive charge</u> on the nitrogen and with this charge, the methylamine <u>loses all his nucleophilicity.</u>

I hope it helps!

5 0
3 years ago
How many grams of carbon should be burned in an excess of oxygen at stp to obtain 2. 21 l of carbon dioxide?.
snow_tiger [21]
You must burn 1.17 g C to obtain 2.21 L CO2 at
STP.
The balanced chemical equation is
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Step 1. Convert litres of CO, to moles of CO2.
STP is 0 °C and 1 bar. At STP the volume of 1 mol
of an ideal gas is 22.71 L.
Moles of CO2= 2.21 L CO2 × (1 mol CO2/22.71 L
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Step 2. Use the molar ratio of C:CO2 to convert
moles of CO to moles of C
Moles of C= 0.097 31mol CO2 × (1 mol C/1 mol
CO2) = 0.097 31mol C
Step 3. Use the molar mass of C to calculate the
mass of C
Mass of C= 0.097 31mol C × (12.01 g C/1 mol C) =
1.17 g C
It looks as if you are using the old (pre-1982)
definition of STP. That definition gives a value of
1.18 g C.
4 0
2 years ago
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Iteru [2.4K]

Answer:

its 725 grams 0.0002 725.000

Explanation:

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2 years ago
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Anettt [7]
Initial volume is 8.5. Could I get best answer??
3 0
3 years ago
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An increase in the number of gas molecules in the same volume container increases pressure. A decrease in container volume increases gas pressure. An increase in temperature of a gas in a rigid container increases the pressure.
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