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3 years ago

12

How many ways can five people, a,b,c,d, and e, sit in a row at a movie theater if c must sit to the right of but not necessarily

next to b?

2 answers:

Snezhnost [94]3 years ago

8 0

Answer:

a,b,c,d,e

a,b,d,c,e

a,b,d,e,c

b,a,d,e,c

b,d,a,e,c

b,d,e,a,c

hichkok12 [17]3 years ago

7 0

A,b,c,d,e
a,b,d,c,e
a,b,d,e,c
b,a,d,e,c
b,d,a,e,c
b,d,e,a,c

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No, they did not eat the same amount. Barry ate less because his sandwich was smaller, so there would be a smaller half. Jonah ate more because his sandwich was bigger, so he would have eaten a bigger half.

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3 years ago

What units could you use to measure the height of a hexagonal prism?

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3 years ago

Find the number which when divided by 4 and increased by 12 is the same as when it is divided by 3 and decreased by 5

MatroZZZ [7]

Step-by-step explanation:

Let's make the number we're finding to be $a$ . So, it says that it will be divided by 4 and then added by 12 if we want this in algebraic expression it will be $\frac{a}{4} +12\\$ . It's also telling us that that expression is the same thing as our number divided by 3 and subtracted by 5. If we want an expression out of it it well be $\frac{a}{3} -5\\$ . Since they are the same, we have the equation below.

$\frac{a}{4} +12 = \frac{a}{3} -5\\$

All we have to do now is to find $a$ .

$\frac{a}{4} +12 = \frac{a}{3} -5 \\ \frac{a +48}{4} = \frac{a -15}{3} \\ (3)(a +48) = (a - 15)(4) \\ 3a +144 = 4a -60 \\ (60 -3a) + 3a +144 = 4a -60 +(60 -3a) \\ a = 204$

<h3>Answer:</h3>

Our number must be $204$ . I think

5 0

3 years ago

Explain how comparan

Umnica [9.8K]

How to comparan? Not sure

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3 years ago

Read 2 more answers

30 POINTS!! ASAP! PLS SHOW WORK

sp2606 [1]

Answer:

QII

Step-by-step explanation:

We can use the acronym: ASTC or All Students Take Calculus.

The first letter of each word tells us details within a certain quadrant.

All trig functions in QI will be positive.

Only sine (and cosecant) will be positive in QII.

Only tangent (and cotangent) will be positive in QIII.

And only cosine (or secant) will be positive in QIV.

We know that tan(θ)<0. In other words, it's negative.

So, it our angle θ <em>cannot</em> be in QI or QIII.

We also know that cos(θ)<0.

So, this removes QIV, since in QIV, cosine is positive.

Therefore, the only choices that remains is QII.

In QII, sine is positive, tangent is negative, and cosine is negative.

This fits all our conditions, so θ is in QII.

And we're done!

3 0

3 years ago