Identify the breed of goat in the picture.

Two 2.0-cm-diameter insulating spheres have a 6.60 cm space between them. One sphere is charged to + 76.0 nC , the other to - 30

e-lub [12.9K]

Answer:

$5.2\times 10^5N/C$

Explanation:

Since the two charged bodies are symmetric, we can calculate the electric field taking both of them as point charges.

This can be easily seen if we use Gauss's law, $\int{E} \, dA=\frac{Q_{enclosed}}{\epsilon_o}$

We take a larger sphere of radius, say r, as the Gaussian surface. Then the electric field due to the charged sphere at a distance r from it's center is given by,

$E=\frac{1}{4\pi r^2} \frac{Q_{enclosed}}{\epsilon_o}$

which is the same as that of a point charge.

In our problem the charges being of opposite signs, the electric field will add up. Therefore,

$E_{total}=\frac{1}{4\pi\epsilon_o}\frac{q_1+q_2}{r^2}= (9\times10^9) \frac{(76+30)\times10^{-9}}{((1+3.3)\times10^{-2})^2}N/C =5.2\times10^5N/C$

where, $r$ = distance between the center of one sphere to the midpoint (between the 2 spheres)

8 0

3 years ago

Oberon is a moon of Uranus. It has a mass of 3.01 x 1021 kg and is 761.4 km away from Uranus. If the force of gravity

ZanzabumX [31]

Answer:

acc to formula= F= G m1m2/rsq

mass of Uranus= F×r sq/G×m

M=3.00×10^25×761.4×761.4×10^6/6.67×10^ -11×3.01×10^21

=3×10^25-8×7614×7614/667×301×10^-2-11+21-2

=173918988×10^11/200767

=866×10^11(approx)

4 0

3 years ago

What is measurement

Schach [20]

Answer:

Measurements refers to a process which typically involves identifying and determining the dimensions of a physical object.

Explanation:

A scientific method can be defined as a research method that typically involves the use of experimental and mathematical techniques which comprises of a series of steps such as systematic observation, measurement, and analysis to formulate, test and modify a hypothesis.

Measurements refers to a process which typically involves identifying and determining the dimensions of a physical object.

Basically, the dimensions include important parameters such as width, height, length, area, volume, circumference, breadth, etc.

7 0

3 years ago

Which of the following statements are true for electric field lines? Check all that apply. Check all that apply. Electric field

Scilla [17]

Answer:

Electric field lines point away from positive charges and toward negative charges. True

Electric field lines are continuous; they do not have a beginning or an ending. False

Electric field lines can never intersect. True

Electric field lines are close together in regions of space where the magnitude the electric field is weak and are father apart where it is strong. False

At every point in space, the electric field vector at that point is tangent to the electric field line through that point. True

Explanation:

Electric field lines point away from positive charges and toward negative charges. Always the field lines go to negative charges and leave from positive charges.

Electric field lines are continuous; they do not have a beginning or an ending. False

Because the field lines starts at positive charges and ends in negative charges.

Electric field lines can never intersect. True

It can not intercept the field lines because in that point the the field would have two directions. Besides, in that point the real value of the field should be found adding both field lines.

Electric field lines are close together in regions of space where the magnitude the electric field is weak and are father apart where it is strong. False

This fact is opposite to that so the regions of space where the magnitude the electric field is weak the lines are father apart and where the field is strong the lines are close together.

At every point in space, the electric field vector at that point is tangent to the electric field line through that point. True

This statement correspond to the definition of the field line.

5 0

3 years ago

g A wave pulse on a light string encounters a boundary with a heavy string. In other words, the pulse moves from a medium with a

sammy [17]

Answer:

The answer to the question is

Changing travel medium from one of low density to another of higher density (heavier weight) reduces the speed of the transmitted pulse

Explanation:

The rate of propagation of a wave in a medium is correlated to the properties of the medium. in a guitar, sound is produced by vibrating the string. The frequency of the produced sound depends on the speed and wavelength of the wave as follows

v = f × λ

The guitar strings, though having equal length, the produce sounds of different frequencies and they also have different linear mass density.

As highlighted, the speed of sound is a function function of the frequency and the frequency produced in a string is related to the linear density

The relation between speed with linear density of a material, or its mass per unit length is

v absolute = $\sqrt{\frac{F_{T} }{\mu} }$ where

v absolute = The absolute velocity

$F_{T}$ = The horizontal tension on the string

$\mu$ = Mass per unit length of the string = $\frac{m}{l}$ where

m = Mass of the string and

l = Length of the measured mass of string

There fore the wave propagates more slowly, or slows down when it changes its travel medium from one of lower linear mass density to a different medium having a higher density

The speed of the transmitted pulse reduces in the heavier string

8 0

3 years ago