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3 years ago

I dont understand physics.

Physics

1 answer:

Elanso [62]3 years ago

8 0

Answer:

same but from what i know is the newtons thingy

Explanation:

hope that helps!

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A 1.2 kg block is held at rest against the spring with a force constant k= 730 N/m. Initially, the spring is compressed a distan

Nesterboy [21]

Answer:

Compression distance: $d \approx 0.102\,m$

Explanation:

According to this statement, we know that system is non-conservative due to the rough patch. By Principle of Energy Conservation and Work-Energy Theorem, we have the following expression that represents the system having a translational kinetic energy ( $K$ ), in joules, at the expense of elastic potential energy ( $U$ ), in joules, and overcoming work losses due to friction ( $W_{l}$ ), in joules:

$K + W_{l} = U$ (1)

By definitions of translational kinetic and elastic potential energies and work losses due to friction, we expand the equation described above:

$\frac{1}{2}\cdot m \cdot v^{2} +\mu\cdot m\cdot g \cdot s = \frac{1}{2} \cdot k \cdot d^{2}$ (2)

Where:

$m$ - Mass of the block, in kilograms.

$v$ - Final velocity of the block, in meters per second.

$\mu$ - KInetic coefficient of friction, no unit.

$g$ - Gravitational acceleration, in meters per square second.

$s$ - Width of the rough patch, in meters.

$k$ - Spring constant, in newtons per meter.

$d$ - Compression distance, in meters.

If we know that $m = 1.2\,kg$ , $v = 2.3\,\frac{m}{s}$ , $\mu = 0.44$ , $g = 9.807\,\frac{m}{s^{2}}$ , $s = 0.05\,m$ and $k = 730\,\frac{N}{m}$ , then the compression distance of the spring is:

$\frac{1}{2}\cdot m \cdot v^{2} +\mu\cdot m\cdot g \cdot s = \frac{1}{2} \cdot k \cdot d^{2}$

$m\cdot v^{2} + 2\cdot m\cdot g \cdot s = k\cdot d^{2}$

$d = \sqrt{\frac{m\cdot (v^{2}+2\cdot g\cdot s)}{k} }$

$d \approx 0.102\,m$

4 0

3 years ago

Which tool would be most useful to identify areas with frequent earthquakes to predict future earthquakes?

enyata [817]

It is a seismograph that would be most useful.

6 0

3 years ago

What does the "c^2" mean in E=mc^2? *

Korolek [52]

Answer:

C.speed of light times 2

4 0

3 years ago

In a race, a runner traveled 12 meters in

Nastasia [14]

Since it is a race, the runner start from rest, so we can use the Velocity Hourly Equation to describle yours moviment.

$S=S_{o}+V_{o}t+ \frac{at^2}{2} \\ S=\frac{at^2}{2}$

Entering the unknowns, we have:

$S=\frac{at^2}{2} \\ 12*2=a*4^2 \\ \boxed {a=1.5m/s^2}$

Number 2

If you notice any mistake in my english, please let me know, because i am not native.

3 0

3 years ago

The first nucleus of an atom was shown as?

postnew [5]

<h2>Answer: A solid mass</h2>

The first atomic model was the one proposed by Jhon Dalton, according to which it is postulated that:

"Matter is made up of indivisible, indestructible and extremely small particles called atoms."

That is, the atom is a solid and indivisible mass.

However, over time some limitations were found in Dalton's atomic model and was replaced by the Thomson's atomic model, then by Rutherford's, Bohr's, Sommerfield's, and finally Shrodinger's.

Currently it is known that each atom is composed of a nucleus and one or more electrons attached to the nucleus, which is composed of one or more protons and typically a similar number of neutrons.

In addition, the atomic nucleus is the central part of the atom and concentrates most of the total mass of the atom.

Therefore, the correct option is A.

6 0

4 years ago

Read 2 more answers