Answer:
the above picture might help
Answer:
1) Q ’= 8 Q
, 2) q ’= 16 q
, 3) r ’= ¾ r
Explanation:
For this exercise we will use Coulomb's law
F = k q Q / r²
It asks us to calculate the change of any of the parameters so that the force is always F
Original values
q, Q, r
Scenario 1
q ’= 2q
r ’= 4r
F = k q ’Q’ / r’²
we substitute
F = k 2q Q ’/ (4r)²
F = k 2q Q '/ 16r²
we substitute the value of F
k q Q / r² = k q Q '/ 8r²
Q ’= 8 Q
Scenario 2
Q ’= Q
r ’= 4r
we substitute
F = k q ’Q / 16r²
k q Q / r² = k q’ Q / 16 r²
q ’= 16 q
Scenario 3
q ’= 3/2 q
Q ’= ⅜ Q
we substitute
k q Q r² = k (3/2 q) (⅜ Q) / r’²
r’² = 9/16 r²
r ’= ¾ r
Answer:
When the pressure and the temperature are increased the volume is 285.7 ml.
Explanation:
We can find the new volume by using the Ideal Gas Law:

Where:
P: is the pressure
V: is the volume
n: is the number of moles
R: is the gas constant
T: is the temperature
Initially, when V₁ = 200 ml, P₁ = 500 torr and T₁ = 10 °C, we have:
(1)
And finally, when P₂ = 700 torr and T₂ = 20 °C, we have:
(2)
By equating (1) with (2):
Therefore, when the pressure and the temperature are increased the volume is 285.7 ml.
I hope it helps you!
Answer
given,
angle with horizontal = 12°
constant speed with the slope = 1 m/s
Work on the skier to move 8 m = 900 J
a) Rope moved with constant speed
change in kinetic energy is equal to zero
work done by the force of the rope = 900 J
rate of force of the rope when skier move with
b) v = 1 m/s total time t = 8 s
Power =
=
= 112.5 W
c) v = 2 m/s total time t = 8/2 = 4 s
Power =
=
= 225 W
Answer:
The maximum electric field strength is 0.0144 V/m.
Explanation:
Given that,
Electric potential created in the heart, V = 3.6 mV
Distance, d= 0.25 m
Frequency of the the electromagnetic wave, f = 1 Hz
We need to find the maximum electric field strength created. We know that the electric potential is given by :

E is the maximum electric field strength

So, the maximum electric field strength is 0.0144 V/m. Hence, this is the required solution.