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3 years ago

Which of the following had have the highest viscosity ?

2 answers:

5 0

Hello There

Answer: Corn Syrup (B)

Reason: Corn syrup has high viscosity because it is made out of corn which is mixed with acidic water, which is then mixed with enzymes, and then heated and pressed to get the liquid from the corn,

I hope this helps
-Chris

Julli [10]3 years ago

4 0

Which of the following had have the highest viscosity ?
B) corn syrup bevause corn syrup is a mixture of 2 elements

You might be interested in

Who created the theory of general relativity?

pantera1 [17]

Who created the theory of general relativity?:

The answer would be: Albert Einstein.

Albert Einstein developed the general relativity theory (gravitation).

The year he developed the general relativity theory or (GR) was back in 1907 and 1915. Then many other contributions after 1915.

Thanks,

7 0

3 years ago

Read 2 more answers

13. A transformer has a primary coil with 600 turns and a secondary coil with 300 turns. If the output voltage is 320 volts, wha

vivado [14]

His is a step down transformer since n(primary) is greater than n(seconcary). You relate the input voltage with the ouput voltage with the following equation:

Vout = n2/n1*Vin (n2/n1 is essentially your 'transfer function' that dictates what a specified input would produce) 

Solving the equation: 

Vin = Vout*n1/n2 = (320V)*(600/300) = 640 V 

This is checked by seeing if Vin is greater than Vout, which it is for a step down transformer.

5 0

3 years ago

Block B is attached to a massless string of length L = 1 m and is free to rotate as a pendulum. The speed of block A after the c

Amanda [17]

Complete Question

The diagram for this question is shown on the first uploaded image

Answer:

The minimum velocity of A is $v_A= 4m/s$

Explanation:

From the question we are told that

The length of the string is $L = 1m$

The initial speed of block A is $u_A$

The final speed of block A is $v_A = \frac{1}{2}u_A$

The initial speed of block B is $u_B = 0$

The mass of block A is $m_A = 7kg$ gh

The mass of block B is $m_B = 2 kg$

According to the principle of conservation of momentum

$m_A u_A + m_B u_B = m_Bv_B + m_A \frac{u_A}{2}$

Since block B at initial is at rest

$m_A u_A = m_Bv_B + m_A \frac{u_A}{2}$

$m_A u_A - m_A \frac{u_A}{2} = m_Bv_B$

$m_A \frac{u_A}{2} = m_Bv_B$

making $v_B$ the subject of the formula

$v_B =m_A \frac{u_A}{2 m_B}$

Substituting values

$v_B =\frac{7 u_A}{4}$

This $v__B$ is the velocity at bottom of the vertical circle just at the collision with mass A

Assuming that block B is swing through the vertical circle(shown on the second uploaded image ) with an angular velocity of $v__B'$ at the top of the vertical circle

The angular centripetal acceleration would be mathematically represented

$a= \frac{v^2_{B}'}{L}$

Note that this acceleration would be toward the center of the circle

Now the forces acting at the top of the circle can be represented mathematically as

$T + mg = m \frac{v^2_{B}'}{L}$

Where T is the tension on the string

According to the law of energy conservation

The energy at bottom of the vertical circle = The energy at the top of

the vertical circle

This can be mathematically represented as

$\frac{1}{2} m(v_B)^2 = \frac{1}{2} mv^2_B' + mg 2L$

From above

$(T + mg) L = m v^2_{B}'$

Substitute this into above equation

$\frac{1}{2} m(\frac{7 v_A}{4} )^2 = \frac{1}{2} (T + mg) L + mg 2L$

$\frac{49 mv_A^2}{16} = \frac{1}{2} (T + mg) L + mg 2L$

$\frac{49 mv_A^2}{16} = T + 5mgL$

The value of velocity of block A needed to cause B be to swing through a complete vertical circle is would be minimum when tension on the string due to the weight of B is zero

This is mathematically represented as

$\frac{49 mv_A^2}{16} = 5mgL$

making $v_A$ the subject

$v_A = \sqrt{\frac{80mgL}{49m} }$

substituting values

$v_A = \sqrt{\frac{80* 9.8 *1}{49} }$

$v_A= 4m/s$

6 0

3 years ago

Explain how the thermal energy of a swimming pool compares to the thermal energy of a lake at the same temperature.

astra-53 [7]

There is more thermal energy in the lake because there is more water which is more thermal energy

3 0

3 years ago

A toolbox of mass 3.2kg is lowered by a rope from the roof to the ground. Find the acceleration of the toolbox when the force of

Lisa [10]

Answer:

The answer to your question is:

a) 2.7 m/s²

b) -3.6 m/s²

Explanation:

Data

mass of the toolbox = 3.2 kg

a = ?

F = 40 N and F = 20 N

g = 9.81 m/s²

Formula

Second law of motion = F = ma

a + g = F / m

a = F/m - g

a) a = 40/3.2 - 9.81

a = 2.69 ≈ 2.7 m/s² positive up

b) a = 20/ 3.2 - 9.81

a = 6.25 - 9.81

= - 3.56 ≈ - 3.6 m/s² negative down

8 0

3 years ago