Answer:
Velocity.
Explanation:
Projectile motion is characterized as the motion that an object undergoes when it is thrown into the air and it is only exposed to acceleration due to gravity.
As per the question, 'any change in the initial velocity of the projectile(object having gravity as the only force) would lead to a change in the range as well as the maximum height of the projectile.' To illustrate numerically:
Horizontal range: As per expression:
R= (*sin2θ)/g
the range depending on the square of the initial velocity.
Maximum height: As per expression:
H= ( * θ
)/2g
the maximum distance also depends upon square of the initial velocity.
Divide 56 by 60 then x the answer by 6 then you get 5.6km which is your answer.
Answer
given,
discharge rate from pipe = 1000 gallons/minutes
now,
flow rate in cubic meters per second
1 gallon = 0.00378541 m³
1 min = 60 s
Q =
Q = 0.063 m³/s
flow rate in liters per minute
1 gallon = 3.78541 L
Q =
Q = 3785.41 m³/min
flow rate in cubic feet per second
1 gallon = 0.133681 ft³
1 min = 60 s
Q =
Q = 2.23 ft³/s
Explanation:
It is given that,
Force,
Position vector,
(a) The torque on the particle about the origin is given by :
(b) To find the angle between r and F use dot product formula as :
Hence, this is the required solution.