Question

A strong man is compressing a lightweight spring between two weights. One weight has a mass of 2.3 kgkg , the other a mass of 5.3 kgkg . He is holding the weights stationary, but then he loses his grip and the weights fly off in opposite directions. The lighter of the two is shot out at a speed of 6.0 m/sm/s .

Answer 1

Incomplete question.The complete question is here

A strong man is compressing a lightweight spring between two weights. One weight has a mass of 2.3 kgkg , the other a mass of 5.3 kgkg . He is holding the weights stationary, but then he loses his grip and the weights fly off in opposite directions. The lighter of the two is shot out at a speed of 6.0 m/sm/s .What is the speed of the heavier weight?

Answer:

$v_{2f}=2.60m/s$

Explanation:

Given data

First weight mass m₁=2.3 kg

Second weight mass m₂=5.3 kg

Lighter weight speed v₁i= -6.0 m/s

To find

Heavier weight velocity v₂f

Solution

From law of conservation of momentum

$p_{f}=p_{i}\\ m_{1}v_{1f}+m_{2}v_{2f}=m_{1}v_{1i}+m_{2}v_{2i}\\as\\v_{1i}=v_{2i}=0\\So\\ m_{1}v_{1f}+m_{2}v_{2f}=0\\ m_{1}v_{1f}=-m_{2}v_{2f}\\v_{2f}=(\frac{ m_{1}v_{1f}}{-m_{2}} )\\v_{2f}=(\frac{ 2.3kg*(-6.0m/s)}{-(5.3kg)} )\\v_{2f}=(-13.8/-5.3)\\v_{2f}=2.60m/s$