A strong man is compressing a lightweight spring between two weights. One weight has a mass of 2.3 kgkg , the other a mass of 5.
1 answer:
Incomplete question.The complete question is here
A strong man is compressing a lightweight spring between two weights. One weight has a mass of 2.3 kgkg , the other a mass of 5.3 kgkg . He is holding the weights stationary, but then he loses his grip and the weights fly off in opposite directions. The lighter of the two is shot out at a speed of 6.0 m/sm/s .What is the speed of the heavier weight?
Answer:
Explanation:
Given data
First weight mass m₁=2.3 kg
Second weight mass m₂=5.3 kg
Lighter weight speed v₁i= -6.0 m/s
To find
Heavier weight velocity v₂f
Solution
From law of conservation of momentum
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Answer:
a) K = 0.63 J, b) h = 0.153 m
Explanation:
a) In this exercise we have a physical pendulum since the rod is a material object, the angular velocity is
w² =
where d is the distance from the pivot point to the center of mass and I is the moment of inertia.
The rod is a homogeneous body so its center of mass is at the geometric center of the rod.
d = L / 2
the moment of inertia of the rod is the moment of a rod supported at one end
I = ⅓ m L²
we substitute
w =
w =
w =
w = 4.427 rad / s
an oscillatory system is described by the expression
θ = θ₀ cos (wt + Φ)
the angular velocity is
w = dθ /dt
w = - θ₀ w sin (wt + Ф)
In this exercise, the kinetic energy is requested in the lowest position, in this position the energy is maximum. For this expression to be maximum, the sine function must be equal to ±1
In the exercise it is indicated that at the lowest point the angular velocity is
w = 4.0 rad / s
the kinetic energy is
K = ½ I w²
K = ½ (⅓ m L²) w²
K = 1/6 m L² w²
K = 1/6 0.42 0.75² 4.0²
K = 0.63 J
b) for this part let's use conservation of energy
starting point. Lowest point
Em₀ = K = ½ I w²
final point. Highest point
Em_f = U = m g h
energy is conserved
Em₀ = Em_f
½ I w² = m g h
½ (⅓ m L²) w² = m g h
h = 1/6 L² w² / g
h = 1/6 0.75² 4.0² / 9.8
h = 0.153 m
Answer:
a
The speed is
b
The distance is
Explanation:
From the question we are told that
The speed of the banana is
The distance from my location is
The time taken is
The speed of the ice cream is
substituting values
The distance of separation between i and Valdimir is the same as the distance covered by the banana
So
substituting values