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Valentin [98]
3 years ago
12

At a pressure 42 kPa, the gas in a cylinder has a volume of 11 liters. Assuming temperature remains the same, if the volume of t

he gas is decreased to 9 liters, what is the new pressure?
Physics
1 answer:
nlexa [21]3 years ago
5 0
Boyle's law<span> is a gas </span>law<span>, stating that the pressure and volume of a gas have an inverse relationship , when temperature is held constant. That is PV = constant. Therefore, (PV)initial = (PV)final. 42x11 = 9x P(final). P(final) = 42x11/9 = 51.34kPa. </span>
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Answer:

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tankabanditka [31]

Answer:

<h3>The answer is 500 kg</h3>

Explanation:

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We have the final answer as

<h3>500 kg</h3>

Hope this helps you

7 0
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