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Valentin [98]
3 years ago
12

At a pressure 42 kPa, the gas in a cylinder has a volume of 11 liters. Assuming temperature remains the same, if the volume of t

he gas is decreased to 9 liters, what is the new pressure?
Physics
1 answer:
nlexa [21]3 years ago
5 0
Boyle's law<span> is a gas </span>law<span>, stating that the pressure and volume of a gas have an inverse relationship , when temperature is held constant. That is PV = constant. Therefore, (PV)initial = (PV)final. 42x11 = 9x P(final). P(final) = 42x11/9 = 51.34kPa. </span>
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Alexxx [7]

Answer:

The correct answer is inertia.

Explanation:

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Have a nice day!

8 0
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natali 33 [55]

Explanation:

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7 0
2 years ago
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Usimov [2.4K]

Answer:

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Explanation:

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5 0
3 years ago
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Mrrafil [7]
Density is mass per unit volume. In this case, the unit is g/ml
Mass=453g                              ρ=453g/224ml
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Density=?
ρ=mass/volume
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6 0
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Crazy boy [7]
A) 300cm/h
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5cm/min
C)1m=100cm
300/100=3
3m/h
7 0
3 years ago
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