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marshall27 [118]
2 years ago
14

Which one of the following compounds utilizes both ionic and covalent bonding?A) C6H12O6.B) CC32-.C) CO2.D) MgCl2.E) Al2(SO4)3.

Chemistry
1 answer:
JulsSmile [24]2 years ago
8 0

Answer:

Al2(SO4)3

Explanation:

Looking at this carefully, we will discover that Al2(SO4)3 is composed of Al^3+ and SO4^2-.

The aluminum and sulphate ions are ionically bonded. However, the oxygen and sulphur in the sulphate ion are covalently bonded.

Hence, Al2(SO4)3 contains both ionic and covalent bond.

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Calculate the concentration of all ions present in each of the following solutions of strong electrolytes. a. 0.100 mole of Ca(N
pickupchik [31]

Answer:

[Ca²⁺] = 1M

[NO₃⁻] = 2M

Explanation:

Calcium nitrate dissociates in water as follows:

Ca(NO₃)₂ ⇒ Ca²⁺ + 2NO₃⁻

The moles of Ca²⁺ can be found using the molar relationship between Ca(NO₃)₂ and Ca²⁺

(0.100mol Ca(NO₃)₂) (Ca²⁺ /Ca(NO₃)₂) = 0.100 mol Ca²⁺

The concentration of Ca²⁺  is then:

[Ca²⁺] = n/V = (0.100mol)/(100.0mL) x (1000ml)/(1L) = 1M

Similarly, moles of NO₃⁻ can be found using the molar relationship between Ca(NO₃)₂ and NO₃⁻:

(0.100mol Ca(NO₃)₂) (2NO₃⁻/Ca(NO₃)₂) = 0.200 mol NO₃⁻

The concentration of NO₃⁻ is then:

[NO₃⁻] = (0.200mol)/(100.0mL) x (1000ml)/(1L) = 2M

6 0
3 years ago
How many grams of Ca(OH)2are required to make 1.5 L of a 0.81 M solution?
FrozenT [24]

Answer:

Mass = 90.28 g

Explanation:

Given data:

Mass of Ca(OH)₂ = ?

Volume of solution= 1.5 L

Molarity of solution = 0.81 M

Solution:

First of all we will calculate number of moles.

Molarity = number of moles / volume in L

by putting values,

0.81 M = Number of moles / 1.5 L

Number of moles = 0.81 M × 1.5 L

Number of moles = 1.22 mol

Mass of Ca(OH)₂ in gram:

Mass = number of moles × molar mass

Mass = 1.22 mol × 74.09 g/mol

Mass = 90.28 g

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2 years ago
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Answer: sea, more

I hope this helps

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2 years ago
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Equation: 2K + S --> K2S Chemical formula: K2S
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zimovet [89]

There is sufficient evidence to show that Apple violated Section 1 of Sherman Act by making publishers raise price of e-books.

Explanation:

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