Answer:
1088.89 Pa
Explanation:
According to the Newton's second law of motion:-
Mass = 50.0 kg
Acceleration = g = 9.81 m/s²
So,
Force = 490 N
Area of the base = 
= 
m² = 0.45 m²
<u>Pressure = Force/Area = 
= 1088.89 Pa</u>
As given:
Initial moles of P taken = 2 mol
the products are R and Q
at equilibrium the moles of
R = x
total moles = 2 + x/2
Let us check for each reaction
A) P <-> 2Q+R
Here if x moles of P gets decomposed it will give 2x moles of Q and x moles of R
So at equilibrium
moles of P left = 2- x
moles of Q = 2x
moles of R = x
Total moles = (2-x) + 2x + x = 2 +2x
B) 2P <-> 2Q+R
Here x moles of P will give x moles of Q and x/2 moles of R
So at equilibrium
moles of P left = 2- x
moles of Q = x
moles of R = x/2
Total moles = (2-x) + x + x/2 = 2 + x/2
C) 2P <-> Q+R
Here x moles of P will give x/2 moles of Q and x/2 moles of R
So at equilibrium
moles of P left = 2- x
moles of Q = x /2
moles of R = x/2
Total moles = (2-x) + x + x = 2
D) 2P <-> Q+2R
Here x moles of P will give x/2 moles of Q and x moles of R
So at equilibrium
moles of P left = 2-x
moles of Q = x/2
moles of R = x
Total moles = (2-x) + x/2 + x = 2 + x/2
Answer: Andre. If it is used as an antifreeze, one would infer that it's freezing point is less than water.
Explanation:
The freezing point of ethylene glycol alone (100%) is -12.9oC. That is somewhat less than the freezing point of water but nowhere near the freezing point of water containing 70% ethylene glycol.
D. Biased data is likely skewed for or against some variable tested, meaning it isn't an honest study.
The statement that is
untrue concerning a reversible reaction is The reaction always spends equal time in the forward and reverse
direction. The answer is letter B. The reset of the statements are true
concerning the reversible reaction.
