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Anika [276]
3 years ago
12

suppose you increase your walking speed from 5m/s to 14m/s in a period of 1 . what is your acceleration?

Physics
1 answer:
Ne4ueva [31]3 years ago
7 0

Acceleration = (change in speed) / (time for the change.

change in speed = (ending speed) - (starting speed)  =  9 m/s.

Acceleration  =  (9 m/s) / (period of 1) .

We don't know the units of the 'period of 1'.
If it means '1 second', then the acceleration is   9 m/s² .

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Answer:

Δω = -5.4 rad/s

αav = -3.6 rad/s²

Explanation:

<u>Given</u>:

           Initial angular velocity = ωi = 2.70 rad/s

           Final angular velocity = ωf = -2.70 rad/s (negative sign is  

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           Change in time period = Δt = 1.50 s

<u>Required</u>:

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           Average angular acceleration = αav = ?

<u>Solution</u>:

          <u>Angular velocity (Δω):</u>

               Δω = ωf - ωi

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               Δω = -5.4 rad/s.

          <u> Average angular acceleration (αav):</u>

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               αav = -5.4/1.50

              αav = -3.6 rad/s²

Since, the angular velocity is decreasing from 2.70 rad/s (in counter clockwise direction) to rest and then to -2.70 rad/s (in clockwise direction) so, the change in angular velocity is negative.

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3 years ago
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