Julianne’s displacement from her origin is equal to 10.015 kilometers.
<u>Given the following data:</u>
- Distance B = 8.5 km, Northeast.
To calculate Julianne’s displacement from her origin:
<h3>How to calculate displacement.</h3>
We would denote the two (2) unit vectors along the East and Northeast directions by i and j respectively.
<u>Note:</u> Northeast is at angle of 45° with the East.
In terms of vectors, the distances becomes:
Distance A = 2i
![Distance\;B=8.5 [(cos 45i + sin 45j)]\\\\Distance\;B=(\frac{8.5}{\sqrt{2} } i \;+\;\frac{8.5}{\sqrt{2} } j)](https://tex.z-dn.net/?f=Distance%5C%3BB%3D8.5%20%5B%28cos%2045i%20%2B%20sin%2045j%29%5D%5C%5C%5C%5CDistance%5C%3BB%3D%28%5Cfrac%7B8.5%7D%7B%5Csqrt%7B2%7D%20%7D%20i%20%5C%3B%2B%5C%3B%5Cfrac%7B8.5%7D%7B%5Csqrt%7B2%7D%20%7D%20j%29)
<u>For the </u><u>resultant displacement</u><u>:</u>
D = 10.015 kilometers.
Read more on displacement here: brainly.com/question/13416288
No temperature change occurs from heat transfer if ice melts and becomes liquid water (i.e., during a phase change). For example, consider water dripping from icicles melting on a roof warmed by the Sun. Conversely, water freezes in an ice tray cooled by lower-temperature surroundings.
Hope this helped you
Answer:
The unit of charge is the Coulomb (C), and the unit of electric potential is the Volt (V), which is equal to a Joule per Coulomb (J/C).
Explanation:
A) 1 rev = 2π rad. Using this ratio, you can find the rad/s: 1160 rev/min x 2π rad/rev x 1 min/60 s = 121.5 rad/s
b) You can find linear speed from angular speed using this equation (note the radius is half the diameter given in the question): v = ωr = 121.5 rad/s x 1.175 m = 142.8 m/s
c) You can find centripetal acceleration using this equation: a = v^2/r = (142.8 m/s)^2 / 1.175 m = 17 355 m/s^2
Answer:
How far will the electron travel beforehitting a plate is 248.125mm
Explanation:
Applying Gauss' law:
Electric Field E = Charge density/epsilon nought
Where charge density=1.0 x 10^-6C/m2 & epsilon nought= 8.85× 10^-12
Therefore E = 1.0 x 10^-6/8.85× 10^-12
E= 1.13×10^5N/C
Force on electron F=qE
Where q=charge of electron=1.6×10^-19C
Therefore F=1.6×10^-19×1.13×10^5
F=1.808×10^-14N
Acceleration on electron a = Force/Mass
Where Mass of electron = 9.10938356 × 10^-31
Therefore a= 1.808×10^-14 /9.11 × 10-31
a= 1.985×10^16m/s^2
Time spent between plate = Distance/Speed
From the question: Distance=1cm=0.01m and speed = 2×10^6m/s^2
Therefore Time = 0.01/2×10^6
Time =5×10^-9s
How far the electron would travel S =ut+ at^2/2 where u=0
S= 1.985×10^16×(5×10^-9)^2/2
S=24.8125×10^-2m
S=248.125mm
