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natka813 [3]
2 years ago
10

Strontium has density of 2.64 g/cm3 and crystallizes with the face-centered cubic unit cell. Calculate the radius of a strontium

atom in units of picometers.

Physics
1 answer:
pantera1 [17]2 years ago
6 0

Answer:

The radius of strontium atom is

2.14 E-8cm

Explanation:

Go through the attached file for a comprehensive detailed explanation.

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Planet Nine is speculated to be on average 20 times farther away from the Sun than Neptune (on average distance from the Sun). H
saveliy_v [14]

Answer:

The distance is 55.636 billion miles, or 528.2 AU.

Explanation:

Since the distance from the Sun to Neptune is 2.7818 billion miles, the distance from the Sun to Planet Nine would be 20 times that, which is:

d=(20)(2781800000\ miles)=55636000000\ miles

or 55.636 billion miles.

Since 1 astronomical unit (AU) is 93 million miles, that distance is also:

d=(55636000000\ miles)(\frac{1AU}{93000000\ miles})=598.2\ AU

6 0
3 years ago
A proton moves at a constant velocity of 50m/s along the x axis ,through crossed electric and magnetic fields .The magnetic fiel
shusha [124]

Answer:

42 I THE CORRECT ANSWER

Explanation:

BECAUSE I KNOW

6 0
3 years ago
Using your Periodic Table, which element below has the smallest atomic radius? A.) Sodium, B.) Chlorine, C.) Phosphorus, D.) Iro
egoroff_w [7]

Explanation:

Chlorine is the smallest atomic radius

6 0
2 years ago
Read 2 more answers
Onur drops a basketball from a height of 10m on Mars, where the acceleration due to gravity has magnitude of 3.7 m/s^2. We want
denpristay [2]

Answer:

2.32 s

Explanation:

Using the equation of motion,

s = ut+g't²/2............................ Equation 1

Where s = distance, u = initial velocity, g' = acceleration due to gravity of  the moon, t = time.

Note: Since Onur drops the basket ball from a height, u = 0 m/s

Then,

s = g't²/2

make t the subject of the equation,

t = √(2s/g')...................... Equation 2

Given: s = 10 m, g' = 3.7 m/s²

Substitute this value into equation 2

t = √(2×10/3.7)

t = √(20/3.7)

t = √(5.405)

t = 2.32 s.

4 0
3 years ago
Read 2 more answers
calculate the height from which a body is released from rest if its velocity just before hitting the ground is 30 metre per seco
Anna71 [15]

Answer:

height is 45 metres

Explanation:

KE=PE

¹/²mv² = mgh

¹/²v² = gh

but v =30m/s

(30)² / 2 =10h

450=10h

h = 45m

5 0
3 years ago
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