Let d = distance that the fugitive travels to get on the train.
Let t = the time to travel the distance d.
The fugitive starts from rest accelerates at a = 3.8 m/s².
Therefore
(1/2)*(3.8 m/s²)*(t s)² = (d m)
1.9 t² = d (1)
The train travels at constant speed 5.0 m/s.
Therefore
(5.0 m/s)*(t s) = d
5t = d (2)
If the fugitive successfully boards the train, then equate (1) and (2).
1.9t² = 5t
t = 0 or t = 2.6316 s
Ignore t = 0, so t = 2.6316 s.
The speed of the fugitive after 2.6316 s, is
v = (3.8 m/s²)*(2.6316 s) = 10 s
This speed exceeds the maximum speed of the fugitive, therefore the fugitive fails to get on the train.
Answer: The fugitive fails to get on the train.
Answer:
730.4 m
Explanation:
The sound waves travels with a uniform motion (=constant velocity), therefore we can calculate the distance it travels using the formula:

where
d is the distance
v is the speed of the sound wave
t is the time taken
In this problem we have:
v = 332 m/s is the speed of sound in air
t = 2.2 s is the time elapsed
Therefore, the distance between the tower and the person is

Explanation:
i think C . it is twice the size of the object
Answer:
5.72 s
Explanation:
From Newton's law, F = ma
The East is +ve direction, Hence,
F = +8930 N
m = 2290 kg
a = ?
8930 = 2290 × a
a = 8930/2290 = 3.90 m/s²
So, we will find the time it takes the car to stop using the equations of motion
a = 3.90 m/s²
u = initial velocity of the car = - 22.3 m/s (the velocity is to the west)
v = final velocity of the car = 0 m/s (since the car comes to rest)
t = time taken for the car to come to rest = ?
v = u + at
0 = - 22.3 + (3.90)(t)
3.9t = 22.3
t = 5.72 s
The correct answer is
<span>c) very small and very large
Let's see this with a few examples:
1) if we have a very small number, such as
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<span>we see that we can write it easily by using the scientific notation:
</span>

<span>2) Similarly, if we have a very large number:
</span>

<span>we see that we can write it easily by using again the scientific notation:
</span>

<span>
</span>