W=F*s
W=9000*0
W=0
W:Work
F:Force
s:Distance
Answer:
θ_c = 24.4º
Explanation:
To find the critical angle, let's use the law of refraction where index 1 refers to the incident medium (diamond) and index 2 refers to the medium where it is to be refracted (air)
n₁ sin θ₁ = n₂ sin θ₂
for the critical angle the ray comes out refracted parallel to the surface, therefore the angle is
θ₂ = 90
n₁ sin θ₁ = n₂
θ_c = θ₁ = sin⁻¹
the index of refraction of the diamond is tabulated
n₁ = 2.419
let's calculate
θ_c = sin⁻¹ (
)
θ_c = 24.4º
(a) The angular acceleration of the wheel is given by

where

and

are the initial and final angular speed of the wheel, and t the time.
In our problem, the initial angular speed is zero (the wheel starts from rest), so the angular acceleration is

(b) The wheel is moving by uniformly rotational accelerated motion, so the angle it covered after a time t is given by

where

is the initial angular speed. So, the angle covered after a time t=3.07 s is
<h2>
Answer </h2>
The answer to this question is <u>407.5 g</u>
<h2>
Explanation</h2>
- The density of the substance = 1.63 g/ml
- The volum of the substance = 0.25 L
- Mass of the substance = ? (Determined)
We know that

So, 0.25 L will be equal to 250 ml. ( Unit must be same)
Formula




Se, mass of the substance is 407.5 g