Answer:
7.39 m/s
Explanation:
Applying
K.E = 1/2mv²..................... Equation 1
Where K.E = Kinetic Energy, m = mass of the ball, v = velocity of the ball.
Make v the subject of the equation
v = √(2K.E/m)................. Euqation 2
From the question,
Given: K.E = 30 J, m = 1.1kg
Substitute these values into equation 2
v = √(2×30/1.1)
v = √54.54
v = 7.39 m/s
Answer:
The induced emf between two end is
V
Explanation:
Given:
Length of rod
m
Height
m
Magnetic field
T
For finding induced emf,

Where
velocity of rod,
For finding the velocity of rod.
From kinematics equation,

Where
initial velocity, 



Put the velocity in above equation,

V
Therefore, the induced emf between two end is
V
Answer:
45.8 cm
Explanation:
To solve this, we will use the formula
5 / x² = 7/(1 - x)²
5 / x² = 7 / (1 - 2x + x²)
5 / 7 = x² / (1 - 2x + x²)
x = 0.5 * (√(35) - 5) meters
x = 0.5 * (5.916 - 5)
x = 0.5 * (0.916)
x = 0.458 or x = 45.8
Answer:
The answer is "82.2 torr"
Explanation:
moles of Xe:

moles of
:
moles of produced

moles of left
:
Calculate the Pressure:
